Ask question

Ask question

All categories

AleksandrR [38]

3 years ago

5

Help please Gravitation

1 answer:

xxMikexx [17]3 years ago

6 0

Answer:a force of attraction exerted by each particle of matter in the universe on every other particle

Explanation:gravitation describes the attractive force between any two masses

You might be interested in

A green croquet ball of mass 0.50 kg is rolling at +12 m/s. It collides with a blue croquet ball that also

Svetach [21]

Answer:

a) 9.6 m/s

b) 11.7 m/s

c) 12 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum $p_{o}$ must be equal to the final momentum $p_{f}$ :

$p_{o}=p_{f}$ (1)

Where:

$p_{o}=m_{g} V_{o} + m_{b} U_{o}$ (2)

$p_{f}=m_{g} V_{f} + m_{b} U_{f}$ (3)

$m_{g}=0.5 kg$ is the mass of green ball

$m_{b}=0.5 kg$ is the mass of the blue ball

$V_{o}=12 m/s$ is the initial velocity of the green ball

$U_{o}=0 m/s$ is the initial velocity of the blue ball

$V_{f}$ is the final velocity of the green ball

$U_{f}$ is the final velocity of the blue ball

Substituting (2) and (3) in (1):

$m_{g} V_{o} + m_{b} U_{o}=m_{g} V_{f} + m_{b} U_{f}$ (4)

Isolating $U_{f}$ :

$U_{f}=\frac{m_{g} V_{o} - m_{g} V_{f}}{m_{b}}$ (5)

$U_{f}=\frac{m_{g} (V_{o} - V_{f})}{m_{b}}$ (6) This is the equation we will use for the next cases

Knowing this, let's begin with the answers:

a) In this case $V_{f}=2.4 m/s$ and we have to find $U_{f}$

$U_{f}=\frac{0.5 kg (12 m/s - 2.4 m/s)}{0.5 kg}$ (7)

$U_{f}=9.6 m/s$ (8)

b) In this case $V_{f}=0.3 m/s$ and we have to find $U_{f}$

$U_{f}=\frac{0.5 kg (12 m/s - 0.3 m/s)}{0.5 kg}$ (9)

$U_{f}=11.7 m/s$ (10)

c) In this case $V_{f}=0 m/s$ and we have to find $U_{f}$

$U_{f}=\frac{0.5 kg (12 m/s - 0 m/s)}{0.5 kg}$ (11)

$U_{f}=12 m/s$ (12)

4 0

3 years ago

What are five differences between drama and prose

Romashka [77]

Answer:

Drama: it has sadness anger and romance

and

i forgot about Prose =w=

Explanation:

6 0

3 years ago

A law of motion that states that an object at rest stays at rest and one in motion stays

adoni [48]

Answer:

that is the first law of motion or newtons first law of motion

6 0

3 years ago

Every day, every hour, every second one of the most important events in life is going on in your body—cells are dividing. When c

ICE Princess25 [194]

Answer:

the answer to the question is mitosis

3 0

3 years ago

shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const

Contact [7]

Answer:

a) $T=0.40 N$

b) $T=1.9 s$

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

$P=2\pi r=0.94$

$r=\frac{0.94}{2\pi}=0.15 m$

Now, we need to find the angle of the pendulum from vertical.

$tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17$

$\alpha=9.44 ^{\circ}$

Let's apply Newton's second law to find the tension.

$\sum F=ma_{c}=m\omega^{2}r$

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

$Tcos(\alpha)=mg$ (1)

The horizontal equation of motion will be:

$Tsin(\alpha)=m\omega^{2}r$ (2)

a) We can find T usinf the equation (1):

$T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N$

We can find the angular velocity (ω) from the equation (2):

$\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s$

b) We know that the period is T=2π/ω, therefore:

$T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s$

I hope it helps you!

8 0

3 years ago