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AleksandrR [38]
3 years ago
5

Help please Gravitation

Physics
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:a force of attraction exerted by each particle of matter in the universe on every other particle

Explanation:gravitation describes the attractive force between any two masses

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A green croquet ball of mass 0.50 kg is rolling at +12 m/s. It collides with a blue croquet ball that also
Svetach [21]

Answer:

a) 9.6 m/s

b) 11.7 m/s

c) 12 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_{o} must be equal to the final momentum p_{f}:  

p_{o}=p_{f} (1)  

Where:  

p_{o}=m_{g} V_{o} + m_{b} U_{o} (2)  

p_{f}=m_{g} V_{f} + m_{b} U_{f} (3)  

m_{g}=0.5 kg is the mass of green ball

m_{b}=0.5 kg is the mass of the blue ball

V_{o}=12 m/s is the initial velocity of the green ball  

U_{o}=0 m/s is the initial velocity of the blue ball  

V_{f} is the final velocity of the green ball

U_{f} is the final velocity of the blue ball  

Substituting (2) and (3) in (1):

m_{g} V_{o} + m_{b} U_{o}=m_{g} V_{f} + m_{b} U_{f} (4)  

Isolating U_{f}:

U_{f}=\frac{m_{g} V_{o}  - m_{g} V_{f}}{m_{b}} (5)  

U_{f}=\frac{m_{g} (V_{o}  - V_{f})}{m_{b}} (6) This is the equation we will use for the next cases

Knowing this, let's begin with the answers:

a) In this case V_{f}=2.4 m/s and we have to find U_{f}

U_{f}=\frac{0.5 kg (12 m/s  - 2.4 m/s)}{0.5 kg} (7)

U_{f}=9.6 m/s (8)

b) In this case V_{f}=0.3 m/s and we have to find U_{f}

U_{f}=\frac{0.5 kg (12 m/s  - 0.3 m/s)}{0.5 kg} (9)

U_{f}=11.7 m/s (10)

c) In this case V_{f}=0 m/s and we have to find U_{f}

U_{f}=\frac{0.5 kg (12 m/s  - 0 m/s)}{0.5 kg} (11)

U_{f}=12 m/s (12)

4 0
3 years ago
What are five differences between drama and prose​
Romashka [77]

Answer:

Drama: it has sadness anger and romance

and

i forgot about Prose =w=

Explanation:

6 0
3 years ago
A law of motion that states that an object at rest stays at rest and one in motion stays
adoni [48]

Answer:

that is the first law of motion or newtons first law of motion

6 0
3 years ago
Every day, every hour, every second one of the most important events in life is going on in your body—cells are dividing. When c
ICE Princess25 [194]

Answer:

the answer to the question is mitosis

3 0
3 years ago
shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const
Contact [7]

Answer:

a) T=0.40 N

b) T=1.9 s

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

P=2\pi r=0.94

r=\frac{0.94}{2\pi}=0.15 m

Now, we need to find the angle of the pendulum from vertical.

tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17

\alpha=9.44 ^{\circ}

Let's apply Newton's second law to find the tension.

\sum F=ma_{c}=m\omega^{2}r

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

Tcos(\alpha)=mg (1)

The horizontal equation of motion will be:

Tsin(\alpha)=m\omega^{2}r (2)

a) We can find T usinf the equation (1):

T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N

We can find the angular velocity (ω) from the equation (2):

\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s

b) We know that the period is T=2π/ω, therefore:

T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s

I hope it helps you!

8 0
3 years ago
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