Answer:
Explanation:
given
initial velocity u = 4.45m/s
Height = 0.6m
g = 9.8m/s²
Required
final velocity v
Using the equation of motion;
v² = u²-2gH (upward motion of the fish makes g to be negative)
v² = 4.45²-2(9.8)(0.6)
v² = 19.8025-11.76
v² = 8.0425
v = 2.84 m/s
Hence the speed of the fish as it passes a point 0.6 m above the water is 2.84m/s
To get the time, we will use the formula
v = u - gt
2.84 = 4.45 - 9.8t
2.84-4.45 = -9.8t
-1.61 = -9.8t
t = 1.61/9.8
t = 0.164secs
Hence the time taken is 0.164secs
Answer:
it is in explanation part
Explanation:
9
7
3
2
5
8
1
11
14
12
13
<span>The physical feel of H2O is the same regardless of the sample size of the substance. Water feels wet whether it is a single drop or equivalent in volume to an ocean. It is the way the substance feels no matter how much or how little there is present.</span>
Answer:
a) 37.70 m/s
b)710.6 m/s²
Explanation:
Given that ;
Mass of object = 2 kg
Radius of the motion = 2m
Frequency of motion = 3 rev/s
The formula to apply is;
v= 2πrf where v is linear speed
v = 2×π×2×3 =12π = 37.70 m/s
Centripetal acceleration is given as;
a= 4×π²×r×f²
a= 4×π²×2×3²
a=710.6 m/s²
