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Kazeer [188]
3 years ago
7

Answer for a thanks

Physics
1 answer:
mariarad [96]3 years ago
7 0
Well, if your question is how light affects plants,

then you would want to design an experiment that plays aruond with the amount of light a plant gets

thus the thing changing (or variable) would be amount of light
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Cheryl has a mug she says is made up of matter. Heather says that the hot choclate inside the cup is made up of matter too. Keat
dangina [55]

<u>Answer:</u>

Cheryl, Heather and Keaton all are correct.

<u>Explanation:</u>

Everything around you is made of matter and matter is anything that has mass and occupies space or in other words, anything which has volume is called matter.

Here, in the given example, Cheryl, Heather and Keaton all are correct because the mug, the hot chocolate which is inside the mug and the steam coming out of it, all have mass. Therefore, all are correct except for Mikayla.

6 0
3 years ago
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Basalt is pushed into the crust by subduction. It will most likely become _____.
suter [353]
Subduction is, "<span>the sideways and downward movement of the edge of a plate of the earth's crust into the mantle beneath another plate." The basalt would most likely be swallowed up into the ground.
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</span>
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3 years ago
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How many sides does a dodecahedron have?
Serhud [2]

Answer:

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Explanation:

Ayo hope you enjoy

8 0
2 years ago
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If two forces are in the same direction then do they cancel each other out
stellarik [79]
Im pretty sure that they do

3 0
3 years ago
3
Misha Larkins [42]

Hi there!

The maximum deformation of the bumper will occur when the car is temporarily at rest after the collision. We can use the work-energy theorem to solve.

Initially, we only have kinetic energy:

KE = \frac{1}{2}mv^2

KE = Kinetic Energy (J)
m = mass (1060 kg)
v = velocity (14.6 m/s)

Once the car is at rest and the bumper is deformed to the maximum, we only have spring-potential energy:

U_s = \frac{1}{2}kx^2

k = Spring Constant (1.14 × 10⁷ N/m)

x = compressed distance of bumper (? m)

Since energy is conserved:

E_I = E_f\\\\KE = U_s\\\\\frac{1}{2}mv^2 = \frac{1}{2}kx^2

We can simplify and solve for 'x'.

mv^2 = kx^2\\\\x = \sqrt{\frac{mv^2}{k}}

Plug in the givens and solve.

x = \sqrt{\frac{(1060)(14.6^2)}{(1.14*10^7)}} = \boxed{0.0198 m}

3 0
2 years ago
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