A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:
6
Step-by-step explanation:
[x-2]=[4.7-2]=[2.7]=2
f(4.7)=3*2=6
Answer:
I would but my account only let's me share within my school district :/
Step-by-step explanation:
The vertex will be (1,4) I use a graphing calculator to find this answer
1.Binomial
2.Trinomial
3.Binomial
4.Trinomial
FYI a Binomial is where the polynomial has 2 terms, hence the ‘bi’
A Trinomial is where the polynomial has 3 terms, hence the ‘tri’
