Step-by-step explanation:
Using the Intermediate Value Theorem, the following is applied:
"If f(x) is a continuous on interval [a,b] and we have two points f(a) and f(b) then there must be some value c such that f(a)<f(c)<f(b).
So here there must be a c such that

Note: F(c)=0, the questions that the function have a solution between 0 and 1, so that means we must have some value, c such that f(c)=0 that exists
Next, plug in the x values into the function


Since cubic functions are continuous and -4<0<4, then there is a solution c that lies between f(0) and f(1)
Answer:
15 ≤ x - 10
Well, that's how you describe it, and I write it for you.
Answer:
x = 12/13
BC = 140/13
Step-by-step explanation:
If A is the mipoint of BC, then AB is half of BC.
AB = BC / 2
8x − 2 = (3x + 8) / 2
16x − 4 = 3x + 8
13x = 12
x = 12/13
BC = 3x + 8
BC = 3 (12/13) + 8
BC = 36/13 + 104/13
BC = 140/13
The answer is
A. No, because 1 x-value corresponds to 2 different y-values