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Nataly [62]
3 years ago
14

Seven more than one number equals nine less than double that number. Find that number.

Mathematics
2 answers:
yanalaym [24]3 years ago
3 0

Answer: That number is 16.

Step-by-step explanation:

n + 7 = 2n- 9        n represents the number now  solve the question

   + 9            +9        add 9 to both sides

n + 16 = 2n             subtract n from both sides

-n            -n

  16= 1n                     Divide both sides by 1

n= 16

Check:    16 + 7 = 2(16) - 9

                 23 =23

klasskru [66]3 years ago
3 0
Answer:
That number is 16

Explanation:
Step 1 - Write down the information you know

*ps. for this problem we will be using x to represent the unknown number. for future problems, just know that unless a variable has an assigned letter to represent it, you can usually pick whichever letter you’d like

• “Seven more” — “7 +”
• “then one number equals” — “x =”
• “nine less than” — “- 9”
• “double that number” — “2x”

Step 2 - Write an equation using the information you know

x + 7 = 2x - 9

Step 3 - Subtract x from both sides of the equation

x + 7 = 2x - 9
x - x + 7 = 2x - x - 9
7 = x - 9

Step 4 - Add 9 to both sides of he equation and then switch sides

7 = x - 9
7 + 9 = x - 9 + 9
16 = x
x = 16

Now that we have found the value of x, we know that the number is 16.
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3 years ago
2.5(t - 2) - 6 = 9 (solve for the unknown variable)
Elis [28]

2.5(t - 2) - 6 = 9

2.5(t - 2) = 9 + 6 = 15

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t = 6 + 2 = 8

Answer: 8

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3 years ago
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7 0
3 years ago
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Paige launched a ball using a catapult she built. The height of the ball (in meters above the ground) ttt seconds after launch i
agasfer [191]

Answer:

1) Factor form : h(t)=-5t(t-8)

2) 8 second after launch.

Step-by-step explanation:

The height of the ball (in meters above the ground) t seconds after launch is modeled by

h(t)=-5t^2+40t

To find the time when ball hit the ground, we need to find the factor form of the given function.

h(t)=-5t(t-8)

When ball hi the ground, then height of the ball from the ground is 0.

h(t)=0

-5t(t-8)=0

Using zero product property, we get

-5t=0\Rightarrow t=0

t-8=0\Rightarrow t=8

Ball hit the ground at t=0 and t=8. It means ball hit the ground in starting and 8 second after launch.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B2%2C25%7D.1%2C46-2%2C25.0%2C02%5C%5C" id="TexFormula1" title="\sqrt{2,25}.1,46-2,25.
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Answer:

i dont understand what your asking

Step-by-step explanation:

4 0
2 years ago
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