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3 years ago

102,119,107,113,110, x; mean 114

Mathematics

1 answer:

Rom4ik [11]3 years ago

6 0

Answer:

x = 133

Step-by-step explanation:

First, determine what total sum would be needed for the mean to be 114. Do this by multiplying 114 by 6 (bc total number of values in data set includes the variable <em>x</em>).

114 x 6 = 684

Next, add the five known values to get a sum of 551.

Now, just: 684 - 551 = 133

For the mean to be 114, x must equal 133.

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Solve the system y= 4x + 1 and 3x+2y =13

Irina18 [472]

Given :

${\qquad \sf \dashrightarrow y= 4x + 1 \: –––– \sf \: (i)}$

${\qquad \sf \dashrightarrow 3x + 2y = 13 \: –––– \sf \: (ii)}$

Now, Substituing the value of y in equation (ii) :

${\qquad \sf \dashrightarrow \: 3x + 2y = 13 }$

${\qquad \sf \dashrightarrow \: 3x + 2(4x + 1) = 13 }$

${\qquad \sf \dashrightarrow \: 3x + 8x + 2 = 13 }$

${\qquad \sf \dashrightarrow \: 11x + 2 = 13 }$

${\qquad \sf \dashrightarrow \: 11x = 13 - 2 }$

${\qquad \sf \dashrightarrow \: 11x = 11 }$

${\qquad \sf \dashrightarrow \: x = \dfrac{11}{11} }$

${\qquad \sf \dashrightarrow \bf \: x = 1 }$

Now, substituting the value of x in equation (i) :

${\qquad \sf \dashrightarrow y= 4x + 1}$

${\qquad \sf \dashrightarrow y= 4(1) + 1}$

${\qquad \sf \dashrightarrow y= 4 + 1}$

${\qquad \bf \dashrightarrow y= 5}$

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2 years ago

We have a bag that contains 100 balls, 50 of them red and 50 blue. Select 5 balls at random. What is the probability that 3 are

MakcuM [25]

Answer:

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Step-by-step explanation:

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2 years ago

An angle measuring 3.6 radians is drawn in standard position?

tester [92]

Answer:

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Step-by-step explanation: I just took the quiz

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3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

5 0

3 years ago

Read 2 more answers

In his freshman year, Mario earned a C in algebra, a B in English, an A in science, and a C- in geography. As a sophomore, he ea

Leya [2.2K]

from what I know

A=4

B=3

C=2

and a plus adds 0.33 and a minus minuses 0.33

question wants us to find yearly average or average per 1 year

since these grades span over 2 years, we must divide the total average by 2

averagefresh=sum of fresh grades/4 grades per year

averagesoph=sum of soph grades/4 grades per year

yearlyaverage=(averagefresh+averagesoph)/2

freshman:

(C)+(B)+(A)+(C-)=2+3+4+(2-0.33)=10.67

sophomore:

(B+)+(A-)+(C+)+(B-)=(3+0.33)+(4-0.33)+(2+0.33)+(3-0.33)=12

averagefresh=10.67/4=2.6675

averagesoph=12/4=3

yearlyaverage=(2.6675+3)/2=2.83375

so it's about a $B^{-}$ average

7 0

3 years ago