Answer:
Step-by-step explanation:
D bc yes
Answer:
![\sf \dfrac{3}{4y}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B3%7D%7B4y%7D)
Step-by-step explanation:
Simplify:
45 = 5 * 3 * 3
60 = 5 * 3 * 2 * 2
GCF = 5*3 = 15
![\sf \dfrac{45x^2}{60x^2y}=\dfrac{45}{60y}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B45x%5E2%7D%7B60x%5E2y%7D%3D%5Cdfrac%7B45%7D%7B60y%7D)
![\sf =\dfrac{45 \div 15}{60y \div 15}\\\\= \dfrac{3}{4y}](https://tex.z-dn.net/?f=%5Csf%20%3D%5Cdfrac%7B45%20%5Cdiv%2015%7D%7B60y%20%5Cdiv%2015%7D%5C%5C%5C%5C%3D%20%5Cdfrac%7B3%7D%7B4y%7D)
I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer:
hi sorry but i dont know what is the answer
Step-by-step explanation:
im very very sorry
The domain is about how far left-to-right the graph goes.
In relation to the x-axis, the graph starts at x = –3 (with an open circle at –3) and then continues over to the right forever.
This is the shown in the picture with the red markup.
In interval notation, this is (-3, infinity).
Remember to use that left-to-right orientation for interval notation!
The range is in turn about how low to how high the graph goes.
On the graph, I’d do the same thing I did on the red marked up graph and compare the graph to the y-axis.
The graph starts down at y = –5 (with an open circle at –5) and then continues on up forever.
In interval notation, this is (-5, infinity).