The first given equation is: x - 7y = -20 We can rewrite this equation as follows: x = 7y - 20 ...........> equation I
The second given equation is: -3x + 9y = 36 ..........> equation II
Substitute with equation I in equation II to get the value of the y as follows: -3x + 9y = 36 -3(7y-20) + 9y = 36 -21y + 60 + 9y = 36 -12y = 36-60 = -24 y = (-24) / (-12) = 2
Now use the value of the y and substitute in equation I to get the value of the x as follows: x = 7y - 20 x = 7(2) - 20 = 14 - 20 = -6
The two methods of solving systems of equations are elimination and substitution. It looks like substitution will be easier here, so I'm going to use that method. I'll take the first term and isolate x, like so:
x - 7y = -20 (original equation) x - 7y + 20 = 0 (subtract 20 from both sides) -7y + 20 = -x (subtract x from both sides) 7y - 20 = x (divide both sides by -1)
Now what we can do it plug this expression into the second equation for x and solve for y:
-3(7y - 20) + 9y = 36 (substitute the expression for x) -21y + 60 + 9y = 36 (distribute the -3) -21y + 9y = -24 (subtract 60 from both sides) -12y = -24 (combine like terms) y = 2 (divide both sides by -12)
Now that we have y, we can substitute it back into the first equation to find x:
x - 7(2) = -20 (substitute your value for y into the equation) x - 14 = -20 (multiply) x = -6 (add 14 to both sides)
Finally, we must check our work by plugging our values back into both of the original equations:
