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Lapatulllka [165]
3 years ago
7

The box-and-whisker plot shows how many problems were missed on a test. What is the DIFFERENCE of the interquartile ranges for T

est 1 and Test 2? *
Mathematics
1 answer:
VMariaS [17]3 years ago
3 0

WE NEED THE QUESTION

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A) name the transversal connecting 1 and 5
lubasha [3.4K]

Answer:

a) Name the transversal connecting 1 and 5. Line r b) Name the transversal connecting 7 and 14. Line q c) Name the transversal connecting 8 and 11. Line s d) Name the transversal connecting 6 and 15. Line q e) Name the transversal connecting 3 and 9. Line p

Step-by-step explanation:

8 0
3 years ago
Through: (4,4), slope<br> 9/4
faltersainse [42]

Answer:

y - 4 = (9/4)(x - 4)

Step-by-step explanation:

Here we're given the slope (9/4) of a line and one point (4, 4) on the line.  The easiest form of the equation of a straight line to use here is the point-slope form:

y - k = m(x - h).

Here h = 4 and k = 4; the slope is m = 9/4.

Thus, the desired equation is

y - 4 = (9/4)(x - 4)

4 0
2 years ago
Please help!!!!
Flauer [41]

The cotangent function is defined as the length of the side adjacent over the length of the side opposite.

Step-by-step explanation:

The sine of an angle is defined as the length of the side opposite over the length of the hypotenuse.

The cosine of an angle is defined as the length of the side adjacent over the length of the hypotenuse.

The tangent of an angle is defined as the length of the side opposite over the length of the side adjacent.

The cotangent function is defined as the length of the side adjacent over the length of the side opposite.

The secant of an angle is defined as the length of the hypotenuse over the length of the side adjacent.

The cosecant of an angle is defined as the length of the hypotenuse over the length of the side opposite.

4 0
3 years ago
Help please <br>I DONT understand <br>​
RideAnS [48]

Answer:

it is B i thinkif im wrong im sorry

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
in a program designed to help patients stop smoking 232 patients were given sustained care and 84.9% of them were no longer smok
grandymaker [24]

Answer:

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

Step-by-step explanation:

1) Data given and notation

n=232 represent the random sample taken

X represent the adults were no longer smoking after one month

\hat p=0.849 estimated proportion of adults were no longer smoking after one month

p_o=0.80 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.8.:  

Null hypothesis:p=0.8  

Alternative hypothesis:p \neq 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

6 0
3 years ago
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