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Anna [14]
3 years ago
13

If you apply a net force of 5N on a cart with a mass of 5 kg, show that the acceleration is 1 m/s2.

Physics
1 answer:
Svetlanka [38]3 years ago
3 0

Answer: F = 5kg x 1 m/s2 = 5 N

Explanation:

Hi, to answer this question we have to apply the next formula:

Force (F) = mass x acceleration

Replacing with the values given and solving for F (force)

F = 5kg x 1 m/s2 = 5 kgm/s2

Since 1 Newton (N) = 1 kgm/s2

F = 5N

Feel free to ask for more if needed or if you did not understand something.  

You might be interested in
A straight, nonconducting plastic wire 9.50 cm long carries a charge density of 130 nC/m distributed uniformly along its length.
Leviafan [203]

Answer:

A) E = 3.70*10^{4} N/C

B)  E = 2.281*10^3 N/C

Explanation:

given data:

charge density \lambda = 130*10^{-9} C/m

length of wire = 9.50 cm

a) at x  = 4.5 m above midpoint, electric field is calculated as

E = \frac{1}{ 2\pi \epsilon} * \frac{ \lambda}{x\sqrt{(x^2/a^2)+1}}

x = 4.5 cm

midpoint a = 4.5 cm = 0.0475 m

E =2{\frac{1}{ 8.99*10^9} * \frac{130*10^{-9} }{0.045\sqrt{(4.5^2/4.75^2)+1}}

E = 3.70*10^{4} N/C

B) when wire is in circle form

Q = \lambda * L

= 130*10^{-9} *9.5*10^{-2}

   = 1.235*10^{-8} C

Radius of circle

r = \frac{L}{2\pi}

r = \frac{9.5*10^{-2}}{2\pi}

r = 1.511*10^{-2} m

E = \frac{1}{ 2\pi \epsilon} * \frac{Qx}{(x^2+r^2)^{3/2}}

E =8.99*10^{9} * \frac{1.23*10^{-8}*4.5*10^{-2}}{((4.5*10^{-2})^2+(1.511*10^{-2})^2)^{3/2}}

E = 2.281*10^3 N/C

6 0
3 years ago
A train travels 81 kilometers in 2 hours and then 90 kilometers in two hours. wat is the average speed
oee [108]
I'm assuming your question refers to the train travels 81 km in 2 hours, as in that's the total distance covered versus the speed for those 2 hours, whereas the 90 km in 2 hours the second time around is the total distance not speed I would assume.

Now... if it was going 81 km for the first 2 hours and 90 km for the second 2 hours then the average speed would be the mean of these numbers, with that being 85.5 km. Though, I doubt that's your question.

With that said, 81 km covered by 2 hours and 90 km covered by 2 more hours. To acquire the km an hour average, we'll have to divide the distance by how many hours it traveled:
81 / 2 = 40.5
90 / 2 = 45

Meaning the train was going 40.5 km an hour for the first 2 hours and 45 km an hour for the second 2 hours. Now, to find the mean:
40.5 + 45 = 85.5 / 2 = 42.75

In-case you were wondering, the mean is the sum of all the numbers in a set, divided by the total amount of numbers in that set, take for instance:
3, 5, 9, 2, 1, 5. -> There are 6 numbers in this set.
3 + 5 + 9 + 2 + 1 + 5 = 25 -> 25 is the sum of these numbers.
25 / 6 = 4.2 (estimated) -> 4.2 is roughly the mean or average between the original set.

Anyhow, with that aside the average speed between this I would believe would be 42.75 km an hour. I hope that helps, have a great rest of your day! ^ ^
| | Ghostgate (Alter) | |
5 0
3 years ago
An unknown element is found to have two naturally occurring isotopes, 200X and 210X with atomic masses of 200.028 and 210.039 re
Kruka [31]

Answer:

The average atomic mass of X is 206.0346

Explanation:

Atomic mass of 200X = 200.028

% abundance of 200X = 40% = 40/100 = 0.4

Atomic mass of 210X = 210.039

% abundance of 210X = 100% - 40% = 60% = 60/100 = 0.6

Average atomic mass of X = (0.4×200.028) + (0.6×210.039) = 80.0112 + 126.0234 = 206.0346

5 0
4 years ago
You and your partner want to investigate how the mass of various sports balls will impact their force as they accelerate down a
luda_lava [24]

The mass of the ball is inversely proportional to acceleration of a ball.

<h3>What is friction?</h3>

This question is incomplete but I will try to help you the much I can. Friction is the force that opposes motion. Friction depends on the nature of the surfaces in contact.

When the mass of the ball is large, the acceleration of the ball decreases since mass is inversely proportional to acceleration of a body.

Learn more about acceleration: brainly.com/question/2437624

6 0
3 years ago
According to the nebular theory of solar system formation, what key difference in their early formation explains why the jovian
svp [43]

Answer:

The Jovian planets formed beyond the Frostline while the terrestrial planets formed in the Frostline in the solar nebular

Explanation:

The Jovian planets are the large planets namely Saturn, Jupiter, Uranus, and Neptune. The terrestrial planets include the Earth, Mercury, Mars, and Venus. According to the nebular theory of solar system formation, the terrestrial planets were formed from silicates and metals. They also had high boiling points which made it possible for them to be located very close to the sun.

The Jovian planets formed beyond the Frostline. This is an area that can support the planets that were made up of icy elements. The large size of the Jovian planets is as a result of the fact that the icy elements were more in number than the metal components of the terrestrial planets.

3 0
3 years ago
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