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kodGreya [7K]
4 years ago
5

HELP!!!

Physics
1 answer:
abruzzese [7]4 years ago
6 0

17.7m/s

Explanation:

Given parameters:

Height of branch = 16m

Unknown:

Velocity before falling = ?

Solution:

We are going to use the appropriate motion equation to solve this problem.

The bird is falling in line with the action of gravity.

Initial velocity is 0 for the bird.

Let the velocity during flight = V;

 Then;

             V² = U²  + 2gH

since U = 0

      V² = 2gH

    V is the unknown velocity

     H is the height of fall

     g is the acceleration due to gravity

    V = √2gH = √ 2x9.8 x 16 = 17.7m/s

learn more:

Velocity brainly.com/question/4460262

#learnwithBrainly

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What are 3 subatomic particles of an atom?
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Protons, neutrons, and electrons<span> are the three main subatomic particles found in an atom.</span>
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The decibel level of an orchestra is 90 db, and the violin section achieves a level of 80 dB. How does the sound intensity from
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Answer:

The difference in the decibel corresponses to a constant difference in the loudness perceived.

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3 years ago
a spring is compressed 15 centimeters when a 8.5 kilogram weight is set upon it. how much power would be needed to stretch out t
o-na [289]

Answer:

159.38 Watts

Explanation:

Initially;

  • Mass on the spring is 8.5 kg
  • Therefore, compression force is 85 N
  • Compression distance is 15 cm or 0.15 m

But;

F = kx

where F is the force of compression, k is the spring constant and x is the compression distance.

Thus;

k = F/x

  = 85 N ÷0.15

  = 566.67 N/m

We are required to determine the power needed to stretch the same spring for 1.5 m in 4 secs.

Power = Work done ÷ time

Work done is given by 0.5kx²

Therefore;

Power = 0.5kx²÷ t

          = (0.5×566.67 N/m × 1.5² ) ÷ 4 seconds

          = 159.38 Watts

Thus, the power needed is 159.38 watts

5 0
3 years ago
Assuming the diode is ideal but with a forward voltage drop of. 65 volts, what is the current in ma if v1=0v, and r1=490ω?
weeeeeb [17]

The current in the ideal diode with forward biased voltage drop of 65V is 132.6 mA.

To find the answer, we have to know more about the ideal diode.

<h3>What is an ideal diode?</h3>
  • A type of electronic component known as an ideal diode has two terminals, only permits the flow of current in one direction, and has less zero resistance in one direction and infinite resistance in another.
  • A semiconductor diode is the kind of diode that is used the most commonly.
  • It is a PN junction-containing crystalline semiconductor component that is wired to two electrical terminals.
<h3>How to find the current in ideal diode?</h3>
  • Here we have given with the values,

                       V_2=65V\\V_1=0V\\R_1=490Ohm.

  • We have the expression for current in mA of the ideal diode with forward biased voltage drop as,

                I=\frac{V_2-V_1}{R_1} =\frac{65}{490} =132.6mA

Thus, we can conclude that, the current in mA of the ideal diode with forward biased voltage drop of 65 V is 132.6.

Learn more about the ideal diode here:

brainly.com/question/14988926

#SPJ4

7 0
2 years ago
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