Explanation:
When an object is moving in a circular path, the motion of the object is called uniform circular motion. The object moves under the action of centripetal acceleration. It is given by :

r is the radius of circular path
v is the speed of the object
In uniform circular motion, the object moves with constant speed. Also, the velocity of the object keeps on changing because it changes direction at every instant of time. Also, the object is accelerating due to change in velocity.
So, the correct options are (b) and (c).
Answer:
v = ((M(√2gH)/3m)
Explanation:
Initial Moment of Inertia= Moment of Inertia of Rod
I = (ML²)/3
Linear Velocity of moveable end of the rod, just before collision is given by = v = (√2gH)/L
Initial Angular Momentum, about the point of the suspension:
Li= Iw = {(ML²)/3} . {(√2gH)/L} = {ML(√2gH)}/3
Final Angular Momentum = Li = mvl, where 'v' is the speed of the mass 'm' after the collision
Since the collision is elastic, all momentum will be conserved, which means
Initial Angular Momemtum = Final Angular Momentum
{ML(√2gH)}/3 = mvL
solving for v = {(M)/3m} . {(√2gH)/L}
Answer:
- The speed will be

Explanation:
We can use the following kinematics equation

where
is the final speed,
its the initial speed, a is the acceleration, and d the distance.
The force will be tripled, the force is:

in 1D

Now, for the original problem, we have



For the second problem, we have

starting from the rest, we have the same initial velocity.


As the force is tripled, we have:


But the mass its the same, so


So the acceleration its also tripled.


As the distance traveled by the arrow must also be the same, we have:





And this will be the speed from the arrow leaving the bow.
Speed depends on time and distance.