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DerKrebs [107]
3 years ago
12

If mass 1 is 2.0 m to the right of the fulcrum and weighs 4.0 kg, and mass 2 weighs 6.0 kg, what distance will mass 2 need to be

Physics
1 answer:
STALIN [3.7K]3 years ago
8 0

Explanation:

C 1.33 m to the left

.........................

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A friend asks you how much pressure is in your car tires. You know that the tire manufacturer recommends 30 psi, but it's been a
Rama09 [41]

Answer:

21 psi

Explanation:

The weight of the car is:

W = mg

W = 1000 kg * 9.8 m/s²

W = 9800 N

Divided by 4 tires, each tire supports:

F = W/4

F = 9800 N / 4

F = 2450 N

Pressure is force divided by area, so:

P = F / A

P = (2450 N) / (0.13 m × 0.13 m)

P ≈ 145,000 Pa

101,325 Pa is the same as 14.7 psi, so:

P ≈ 145,000 Pa × (14.7 psi / 101,325 Pa)

P ≈ 21 psi

3 0
3 years ago
How much momentum does a 10 kg object have when is moving 30 m/s
nikklg [1K]
P = m x v

P = 30 x 10
=300
3 0
3 years ago
Cooling causes a material to
e-lub [12.9K]

Answer:

whats the question?

Explanation:

4 0
4 years ago
Read 2 more answers
If the error in the angle is 0.50, the error in sin 90o is​
Sindrei [870]

At the given erro in angle, the error in the measurement of sin 90 degrees would be 0.001.

<h3>Percentage error</h3>

The percentage error of any measurement is obtained from the ratio of the error to the actual measurement.

The error of sin 90 degrees is calculated as follows;

sin 90 = 1

error in measurement = sin(90 - 0.5)

error in measurement = sin(89.5) = 0.999

<h3>Error in sin 90 degrees</h3>

Error in sin 90 degrees = 1 - 0.999

Error in sin 90 degrees = 0.001

Thus, at the given erro in angle, the error in sin 90 degrees would be 0.001.

Learn more about error in measurement here: brainly.com/question/26668346

4 0
3 years ago
Rainwater draining from a neighborhood street initially travels at 4 ft/s through a pipe with a cross-sectional area of 15.7 ft2
Fudgin [204]

Answer:

The  velocity  is v_2  =  0.96 \ ft/s

Explanation:

From the question we are told that

   The initial speed is  v_1  =  4 \ ft/s

   The  cross -sectional area of the first pipe is  A_1  =  15.7 \ ft

   The  cross -sectional area of the second pipe is A_2 =  65.4 \  ft

Generally from continuity equation we have that

     A_1 * v_1 =  A_2  * v_2

So  

     v_2  =  \frac{A_1 *  v_1  }{A_2 }

=>   v_2  =  \frac{15.7  *  4  }{65.4 }

=>   v_2  =  0.96 \ ft/s

6 0
4 years ago
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