No it is not. it is only found in animal products.
Answer:
The intensity of sound at a rock concert is louder than that of a whisper by a factor of 1 x 10¹⁰
Explanation:
Given;
rock concert sound intensity level, β₁ = 120 dB
whisper sound intensity level, β₂ = 20 dB
The sound intensity level is given as;

where;
I₀ is the threshold sound intensity of hearing = 10⁻¹² W/m²
I is the sound intensity
Intensity of sound at rock concert ;

The intensity of sound of a whisper;

Determine the factor by which the intensity of sound at a rock concert louder than that of a whisper

Therefore, the intensity of sound at a rock concert is louder than that of a whisper by a factor of 1 x 10¹⁰
Because the bridges are higher than the roads. :)
4.5 and then your units I forgot that part but the answer is 4.5<span />