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Marta_Voda [28]
3 years ago
8

Explain why the roller coaster’s potential energy is greater at point 1 than at point 4.

Physics
2 answers:
lesya692 [45]3 years ago
5 0
Point 1 is PROBABLY higher up than point 4.

Another possibility is that on the way from Point 1 to point 4,
a lot of people are falling out of the coaster.

We have no way to tell, because you neglected to show us
the picture that goes with this question.  It's important. 
ValentinkaMS [17]3 years ago
5 0

Answer:

Potential energy is directly related to the height of an object. Point 1 is higher than point 4, so the potential energy is greater at point 1.

Explanation:

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ycow [4]

Answer:

they meet from the girl's original position at: 2.37 (meters)

Explanation:

We need to use the Newton's law, exactly the second law that relate force, mass and acceleration as: F=m*a with this we can get both accelerations; solving for acceleration a=\frac{F}{m}. Now a_{girl}=\frac{5.76}{42.3}=0.14 (m/s^{2}) anda_{sled}=\frac{5.76}{7.93}=0.73(m/s^{2}). Then knowing that they both travel at the same time and assuming that the distance among the girl and the sled is: 15.0-x, so, x=\frac{1}{2}*a_{girl}*t^{2} and15.0-x=\frac{1}{2}*a_{sled}*t^{2}, solving for the time we get:t=\sqrt{\frac{2x}{a_{girl} } } and t=\sqrt{\frac{2*(15.0-x)}{a_{sled} } } with this equations we solving for the x that is the distance between the girl and the sled after the apply the force and we get:\sqrt{\frac{2x}{a_{girl}}} = \sqrt{\frac{2*(15.0-x)}{a_{sled} }. Finally we get:\frac{x}{a_{girl} }=\frac{(15.0-x)}{a_{sled} } and replacing the values we have got:\frac{x}{0.14} =\frac{(15.0-x)}{0.73} so 5.33*x=15-x so x=2.37 (meters).

5 0
3 years ago
What are the different kinds of forces?
Anon25 [30]
Gravity, friction, and air resistance are some examples.
6 0
3 years ago
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A line _____ on a typical Speed vs. Time graph means an object is experiencing a constant acceleration.
Savatey [412]

Answer:

The answer should be C. slanted upward to the right.

Hope this helps. :-)

7 0
3 years ago
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An automobile traveling on a straight, level road has an initial speed v when the brakes are applied. In coming to rest with a c
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Answer:

4x

Explanation:

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For first instance,

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for second instance,

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3 years ago
A 2.24x10^3 kg car slows down uniformly from 20.0 m/s to a stop (assume constant acceleration) via a braking force of 8.41x10^3
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