Explain why the roller coaster’s potential energy is greater at point 1 than at point 4.

2 answers:

5 0

Point 1 is PROBABLY higher up than point 4.

Another possibility is that on the way from Point 1 to point 4,
a lot of people are falling out of the coaster.

We have no way to tell, because you neglected to show us
the picture that goes with this question. It's important.

ValentinkaMS [17]3 years ago

5 0

Answer:

Potential energy is directly related to the height of an object. Point 1 is higher than point 4, so the potential energy is greater at point 1.

Explanation:

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A rocket travels at a speed of 14,000 m/s. What is the distance travelled by the rocket in 150s?

kati45 [8]

1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):

$v=\frac{S}{t}$

Rearranging the equation, we can write

$S=vt$

In this problem, v=14000 m/s and t=150 s, so the distance travelled by the rocket is

$S=vt=(14000 m/s)(150 s)=2.1 \cdot 10^6 m$

2) We can solve the second part of the problem by using the same formula we used previously. This time, t=300 s, so we have:

$S=vt=(14000 m/s)(300 s)=4.2 \cdot 10^6 m/s$

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3 years ago

It takes 9 sec for a 10 newton force to move an object 4 meters to the right. What is direction & magnitude of the force

lana66690 [7]

Answer:

the question is wrong

Explanation:

M is not given
after 9 second the acceleration multiply by the time divided by two then multiplied by the time is equal to 4 meter
((10/Mm/s *9s-)

3 0

3 years ago

A metal rod has a moves with a constant velocity of 40 cm/s along two parallel metal rails through a magnetic field of 0.575 T.

love history [14]

Answer:

2.12/R mW

Explanation:

The electrical power, P generated by the rod is

P = B²L²v²/R where B = magnetic field = 0.575 T, L = length of metal rod = separation of metal rails = 20 cm = 0.2 m, v = velocity of metal rod = 40 cm/s = 0.4 m/s and R = resistance of rod = ?

So, the induced emf on the conductor is

E = BLv

= 0.575 T × 0.2 m × 0.4 m/s

= 0.046 V

= 46 mV

The electrical power, P generated by the rod is

P = B²L²v²/R

= B²L²v²/R

So, P = (0.575 T)² × (0.2 m)² × (0.4 m/s)²

= 0.002116/R W

= 2.12/R mW

3 0