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3 years ago

Which kind of air front forms when a warm air mass meets the area of a cooler air mass?

Physics

1 answer:

mihalych1998 [28]3 years ago

8 0

<span>Answer: "a cold front" .
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A car moves in a circular motion and it is subject to a centripetal acceleration of 24 m/s2. If the radius of the circular path

Softa [21]

Answer:

Explanation:

Centripetal acceleration is given by:

$a_{c} = v^{2}/r$

Thus, centripetal acceleration is inversely proportional to the radius. Thus, when radius will double, the centripetal acceleration will be halved.

3 0

3 years ago

Bile helps in the digestion of —————-

Gnoma [55]

Answer:

Bile helps in the digestion of fats

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3 years ago

Read 2 more answers

Couldn’t you technically make infinite speed by putting a car in a vacuum chamber? Since top speed it made by the amount of forc

kakasveta [241]

Answer:

Explanation:

For infinite speed to be achevied, one must have no sink of energy to spend. The source of entropy in this example, is the tires hitting the surface, producing heat and friction. Not to mention that you'd still need fuel to start the car, and an infinite tunnel or track, which would be impossible and speed up to process of energy loss through entropy quicker.

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3 years ago

A coin dropped in the lift it takes time 0.5 s to reach the floor when lift is staionary it takes time t when lift is moving up

BARSIC [14]

Answer:

t₁ > t₂

Explanation:

A coin is dropped in a lift. It takes time t₁ to reach the floor when lift is stationary. It takes time t₂ when lift is moving up with constant acceleration. Then t₁ > t₂, t₁ = t₂, t₁ >> t₂ , t₂ > t₁

Solution:

Newton's law of motion is given by:

s = ut + (1/2)gt²;

where s is the the distance covered, u is initial velocity, g is the acceleration due to gravity and t is the time taken.

u = 0 m/s, t₁ is the time to reach ground when the light is stationary and t₂ is the time to reach ground when the lift is moving with a constant acceleration a.

hence:

When stationary:

$s=\frac{1}{2}gt_1^2\\\\t_1^2=\frac{2s}{g} \\\\When\ moving\ with\ acceleration(a):\\\\s=\frac{1}{2}(g+a)t_2^2\\\\t_2^2=\frac{2s}{g+a}$

Hence t₂ < t₁, this means that t₁ > t₂.

4 0

3 years ago

Using the method of dimension, derive an expression for the velocity of sound waves. assume that the velocitu depends on:

Soloha48 [4]

Answer:

v = K √(E / ρ)

Explanation:

Modulus of elasticity has units of N/m², or kg/m/s².

Density has units of kg/m³.

Velocity has units of m/s.

If we divide modulus of elasticity by density, we can eliminate kg:

E / ρ = [kg/m/s²] / [kg/m³]

E / ρ = [m²/s²]

Taking the square root gets us units of velocity:

√(E / ρ) = [m/s]

Multiply by the constant K:

v = K √(E / ρ)

7 0

3 years ago