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ira [324]
3 years ago
11

A weather balloon is inflated to a volume of 27.2 l at a pressure of 753 mmhg and a temperature of 30.9 ∘c. the balloon rises in

the atmosphere to an altitude where the pressure is 395 mmhg and the temperature is -15.9 ∘c. assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.
Physics
1 answer:
gayaneshka [121]3 years ago
6 0

By idea gas equation we can say

PV = nRT

here P = pressure

V = volume

n = number of moles

R = Avagadro gas constant

T = temperature

So from above expression you can see that for constant number of moleswe can say

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{753*27.2}{273+30.9} = \frac{395*V_2}{273-15.9}

67.4 = 1.54*V_2

V_2 = 43.9 L

So finally the volume will be 43.9 L

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W = Fd

Given W = 750J, F = 125N;

750 = 125d

Solving for d:
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The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed?(a) 16(b
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The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed: 2.

<h3>What is kinetic energy?</h3>
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4 0
1 year ago
Yellow-green light has a wavelength of 560 nm. What is its frequency?
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7 0
3 years ago
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A balloon is ascending at 12.4m/s at a height of 81.3m above the ground when a package is dropped. a) How long did it take to re
tankabanditka [31]

Answer:

3secs

Explanation:

Given the following parameters

height H= 81.3m

Velocity v = 12.4m/s

Required

Time it take to reach the ground

Using the equation of motion

H = ut+1/2gt²

81.3 = 12.4t + 1/2(9.8)t²

81.3 = 12.4t + 4.9t²

4.9t² + 12.4t - 81.3 = 0

Using the general formula to find t

t = -12.4±√12.4²-4(4.9)(-81.3)/2(4.9)

t = -12.4±√153.76+1593.48/2(4.9)

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Hence it took 3secs to reach the ground

5 0
3 years ago
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