Question

A weather balloon is inflated to a volume of 27.2 l at a pressure of 753 mmhg and a temperature of 30.9 ∘c. the balloon rises in the atmosphere to an altitude where the pressure is 395 mmhg and the temperature is -15.9 ∘c. assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.

Answer 1

By idea gas equation we can say

$PV = nRT$

here P = pressure

V = volume

n = number of moles

R = Avagadro gas constant

T = temperature

So from above expression you can see that for constant number of moleswe can say

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

$\frac{753*27.2}{273+30.9} = \frac{395*V_2}{273-15.9}$

$67.4 = 1.54*V_2$

$V_2 = 43.9 L$

So finally the volume will be 43.9 L