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musickatia [10]
3 years ago
5

A bag contains 666 red jelly beans, 444 green jelly beans, and 444 blue jelly beans. If we choose a jelly bean, then another jel

ly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red?
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:

12/91

Step-by-step explanation:

The question is not properly formatted, here is how it should be formatted.

A bag contains 6red jelly beans, 4 green jelly beans, and 4 blue jelly beans. If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red

Step one

This is selection without replacement.

Sample space

6red jelly beans,

4 green jelly beans, and

4 blue jelly beans.

S= 6+4+4= 14

Probability that the first jelly bean will be green = 4/14= 2/7

Without replacement, Probability that the second jelly bean will be red = 6/13

Hence for the two selections the probability is= 2/7*6/13= 12/91

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Answer:

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3 years ago
10. There are nine golf balls numbered from 1 to 9 in a bag. Three balls are randomly selected without replacement to form a 3-d
lbvjy [14]

Answer:

a) 504

b) 56

c) 0.111

Step-by-step explanation:

Data provided in the question:

There are nine golf balls numbered from 1 to 9 in a bag

Three balls are randomly selected without replacement

a) 3-digit numbers that can be formed

= ^nP_r

n = 9

r = 3

= ⁹P₃

= \frac{9!}{9!-3!}

= 9 × 8 × 7

= 504

b)  3-digit numbers start with the digit 1

=  _ _ _

in the above 3 blanks first digit is fixed i.e 1

we and we have 8 choices left for the last 2 digits

Thus,

n = 8

r = 2

Therefore,

= 1 × ⁸P₂

= 1 × \frac{8!}{8!-2!}

= 1 × 8 × 7

= 56

c) Probability that the 3-digit number formed is less than 200

Now,

The number of 3-digit number formed is less than 200 will be the 3-digit numbers start with the digit 1 i.e part b)

and total 3-digit numbers that can be formed is part a)

therefore,

Probability that the 3-digit number formed is less than 200

= 56 ÷ 504

= 0.111

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Where’s point P at though
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