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ratelena [41]
2 years ago
11

Help me somebody if you want to help me

Mathematics
1 answer:
elena55 [62]2 years ago
8 0

Answer:

A=πr²=π·3²≈28.27433

To find the area of a circle, use the equation πr²

The image is a bit blurry so from what I saw r (radius) is 3 otherwise you can use this equation if r is not 3.

If π was replaced with 3.14 the answer is 28.26 ft².

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3<br> 4<br> 5<br> 5<br> (1,-1)?<br> -17<br> 2t<br> -37<br> -44<br> (x + 4.7 - 5<br> -5<br> What does y-5 represent
tresset_1 [31]

Answer:

Please,I don't get your question & kindly be specific

7 0
3 years ago
An angle measures 32° more than the measure of its supplementary angle. What is the measure of each angle?
ValentinkaMS [17]

Answer:

29°; 61°

Step-by-step explanation:

Let one angle  = x°

Other angle = (x + 32)°

x + x + 32 = 90   {given they are complementary}

2x + 32 = 90

2x = 90 -32

2x = 58

x = 58/2

x = 29

One angle  = 29°

Other angle = 29 + 32 = 61°            

7 0
2 years ago
Find the simplified product b-5/2b x b^2+3b/b-5
White raven [17]

Answer:

The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

=bb+3b=b(b+3)

=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

8 0
3 years ago
Read 2 more answers
A cylindrical package to be sent by a postal service can have a maximum combined length and girth (perimeter of a cross section)
dolphi86 [110]

Answer:

radius r = 47/π in

length l = 23.5 in

Step-by-step explanation:

Let us recall that:

Volume of a cylinder = \pi r^2 h --- (1)

The girth g = 2 \pi r + h      ----- (2)

Given that:

height (h) + girth (g) = 141

Then g = 141 - h   ----- (3)

Equating equation (2) and (3), we have:

141 - h = 2πr + h

2h = 141 - 2πr

h = 70.5 - πr      ------ (4)

From, here now, we can now replace the value of h into equation (1)

i.e.

V = πr²(70.5 - πr)

V = 70.5πr² -  π²r³

Taking the differential of the above equation with respect to r, we have:

\dfrac{dv}{dr} = 141 \pi r- 3\pi ^2 r^2

By further differentiation:

\dfrac{d^2v}{dr^2} = 141 \pi - 6\pi ^2 r

Let set \dfrac{dv}{dr}= 0, Then:

141πr - 3π²r² = 0

141πr = 3π²r²

Divide both sides by πr

141 = 3πr

r = 141/3π

r = 47/π in

Replacing the value of r = 47/π into equation (4), we have:

h = 70.5 - πr

h = 70.5 - π(47/π)

h = 70.5 - 47

h = 23.5 in

From equation (3);

h + g = 141

23.5 + g = 141

g = 141 - 23.5

g = 117.5 in

Volume = πr²h

V = π × (47/π )² × 23.5

V = 16523.94 in³

4 0
2 years ago
Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
erik [133]

Answer: 4.25.

Step-by-step explanation:

First subtract 13.09 from the 21.59, giving you 8.5 as the leftover space on the page.

Then divide in half to find the left and right margin.

4 0
2 years ago
Read 2 more answers
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