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3 years ago

A cylinder has a volume of 288 pi cubic meters and a height of 9 meters. What is the area of the base?

Mathematics

2 answers:

Wittaler [7]3 years ago

6 0

Answer:

32 pi square meters

Step-by-step explanation:

Pavlova-9 [17]3 years ago

5 0

Answer:

The area of the base is about 32 square meters

Step-by-step explanation:

V = pi times r^2 times h which is the formula.

Since the volume is 288, and the height is 9 it is,

288 = pi times r^2 times 9,

288/9 = pi times r^2 times 9/9

32/pi = pi/pi times r^2

10.2 = r^2

The square root of 10.2 is about 3.19

Area formula is pi times radius, r^2

3.19 times 3.19 or 3.19^2 = 10.1761

10.1761 times pi is 31.96 which is about 32 square meters.

I hope this helps!

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Read 2 more answers

Line BC has an equation of a line Y equals 2X +3 and F has an equation of a line Y equals -1/2 x+4 these two equations represent

Masja [62]

Answer:

Lines BC and F represent perpendicular lines

Step-by-step explanation:

we have

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the slope of the line BC is $m=2$

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3 years ago

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

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