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Evgen [1.6K]
3 years ago
8

Please awnser questions, no links, no I dont know 2.

Mathematics
1 answer:
uysha [10]3 years ago
4 0
3 boxes of 12″ =36 = 2 boxes of 18″

so shortest height at which the 2 stack will be the same height =36 inches
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Given f(x) = the quantity of 3x minus 1, divided by 2 , solve for f−1(4)
hichkok12 [17]
<span>f(x)=(<span><span>3x−1)/</span>2<----Starter </span></span>
y = (3x-1)/2
switch x and y
x = (3y-1)/2
2x = 3y-1
2x+1 =3y
y = 2/3*x + 1/3 
f^(-1) (x) = 2/3*x + 1/3 
f^(-1) (4) = 2/3*4 + 1/3 = 8/3 + 1/3 = 9/3 = 3

I hope this helps. ;)
3 0
3 years ago
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HELP! What is the radius and diameter of this circle?
dem82 [27]

Answer:

Step-by-step explanation:

the diameter is the measurement that is all the way across the circle which is given to you so the diameter is 7cm. To find the radius it is half the way across the circle so it is half the diameter so in this case the radius would be 3.5cm

8 0
3 years ago
What is the quotient?
nordsb [41]

Answer:

Negative 4 and one-third divided by -3/4

Step-by-step explanation:

-4 1/3 / - 3/4

-4(3) +1 = -13/4

Divided by -3/4

-13/4 (-4/3) = 52/12

4 and 1/3

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3 years ago
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A semi-circle sits on top of a rectangle to form the figure below. Find its area and perimeter. Use 3.14 for .
AfilCa [17]

9514 1404 393

Answer:

  (c)  A = 38.13 square inches; P = 23.42 inches

Step-by-step explanation:

The radius of the circle is half the diameter, so is 3 inches. This means the entire figure will fit in a rectangle 6 inches wide and 4+3 = 7 inches high. The perimeter of such a rectangle is ...

  P = 2(L+W) = 2(7+6) = 26 inches

The area of that rectangle is ...

  A = LW = (7)(6) = 42 square inches

Then area of the given figure is less than 42 square inches, and the perimeter is less than 26 inches. The only answer choice that matches these bounds is ...

  A = 38.13 square inches; P = 23.42 inches

6 0
3 years ago
You roll a die with the sample space S = {1, 2, 3, 4, 5, 6}. You define A as {1 ,4, 6}, B as {1, 3, 4, 5, 6}, C as {1, 5}, and D
Lilit [14]

Answer:

Step-by-step explanation:

Recall that two events A,B are called mutually exclusive if and only if A\cap B = \emptyset (their intersection is empty). They are exhaustive if they are mutually exclusive and their union is the sample space.

Based on this

a) Note that A\cap B = \{1,6\}, so they are not mutually exclusive nor exhaustive.

b) A\cap C = \{1\} so they are not mutually exclusive nor exhaustive.

c) A\cap D = \emptyset, so they are mutually exclusive. Note that A\cup D = \{1,2,3,4,5,6\}=S. Then they are exhaustive.

d) B\cap C = \{1,5\}, so they are not mutually exclusive nor exhaustive.

6 0
4 years ago
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