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trapecia [35]
3 years ago
15

Convert 1.580 hectoliters to deciliters.

Mathematics
2 answers:
PIT_PIT [208]3 years ago
5 0
1,580 Hectoliters =
1,580,000 Deciliters
raketka [301]3 years ago
3 0
1.580 hectoliters = 1580 deciliters
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Questio
Olenka [21]

Answer:

  d = -1/3, 0

Step-by-step explanation:

Subtract the constant on the left, take the square root, and solve from there.

  (6d +1)^2 + 12 = 13 . . . . given

  (6d +1)^2 = 1 . . . . . . . . . .subtract 12

  6d +1 = ±√1 . . . . . . . . . . take the square root

  6d = -1 ±1 . . . . . . . . . . . .subtract 1

  d = (-1 ±1)/6 . . . . . . . . . . divide by 6

  d = -1/3, 0

_____

Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:

  f(x) = (6x+1)^ +12 -13

We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.

4 0
3 years ago
What is the answer to this problem
ladessa [460]
3:5 my answer has to be 20 characters so im just typing the rest of this to answer your question.
7 0
3 years ago
Read 2 more answers
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
KMZ~ KDH; find z.<br> F<br> 21<br> D<br> 6x + 3<br> E 17<br> G<br> 8x-1<br> C
Drupady [299]

Answer:

x=8

Step-by-step explanation:

Triangle DCE is similar to EGF

CE/EF=DE/EG

Substitute

(8x-1)/21=(6x+3)/17

Cross multiply

(8x−1)*(17)=(6x+3)*(21)

136x−17=126x+63

Subtract 126x from both sides

10x−17=63

Add 17 to both sides.

10x−17+17=63+17

10x=80

Divide both sides by 10.

x=8

6 0
3 years ago
Find f (0) if f(t) = t2 – 2t – 5.
Sonbull [250]
Answer is -5.

Explanation- Since t equals 0. You put 0 in place of every t.

0(2)- 2(0)- 5 =
0-0-5= -5
8 0
3 years ago
Read 2 more answers
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