Answer:
The answer to the equation from question 7 is 14.
Step-by-step explanation:
In question 7, we are given an equation.
2³ + (8 - 5)² - 3
First, subtract 5 from 8 in the parentheses.
2³ + 3² - 3
Next, solve the exponents for 2³ and 3².
8 + 9 - 3
Add 8 to 9.
17 - 3
Subtract 3 from 17.
14
So, the answer to this equation from question 7 is 14.
Selection C is appropriate.
_____
Whenever you solve for something, consider what operations are done to that something. Undo them in reverse order.
Here, "a" is
• multiplied by 2
• has -b^2 added
The last operation is adding -b^2, so we undo that first. We undo it by adding its opposite, b^2.
.. x +b^2 = 2a -b^2 +b^2
.. x +b^2 = 2a . . . . . . . . . . . the point is to cancel the -b^2 term on the right.
The operation before that is multiplying "a" by "2". We undo that by multiplying by the reciprocal of 2, which is 1/2.
.. (1/2)*(x +b^2) = (1/2)*2a
.. (x +b^2)/2 = a . . . . . . . . . the point is to cancel the multiplication by 2 on the right.
You will note this matches answer selection C.
<h3>
Answer: 11+3i</h3>
Work Shown:
(5-8i)-(-6-11i)
5-8i+6+11i ....... distribute
(5+6) + (-8i+11i) .... group like terms
11 + 3i ..... combine like terms
