Answer:
inventory impairment/cost of good sold (p/l) $500
Explanation:
IAS 2 requires that inventory be initially recognized at cost including cost of purchase and other necessary cost incurred in getting the inventory to the location where it becomes available for sale.
Subsequently, the item of inventory is carried at the lower of cost or net realizable value (NRV).
Quantity Unit Cost Unit NRV Lower of cost/NRV Amount
Model A 100 $100 $ 120 $100 $10,000
Model B 50 $50 $ 40 $40 $2,000
Model C 20 $200 $210 $200 $4,000
Adjustment required = 50 ($50 - $40)
=$500
This posted as
Debit inventory impairment/cost of good sold (p/l) $500
Credit Inventory account $500
Answer:
$735,000
Explanation:
The fair values of the assets may be used as a basis for determining the amount to be recorded for each of the assets.
This will be in a proportional manner such that the higher the fair value, the higher the actual cost assigned and vice versa to the asset.
Hence the amount to be recorded for the building
= 840,000 / (840,000 + 840,000 + 1,120,000) * $2,450,000
= $735,000
<span>The correct answer is "the elicitation effect."
The Elicitation Effect refers to the process wherein a person gathers intellect or knowledge about a certain process t be able to cope up with it. Based on the given situation, Toni is using elicitation, because he is thinking of what to do during lunch break, yet he waited to see if what the other employees would do during lunch break then he would just follow what they will be doing.</span>
<span>25 years: No Payment, but total is 250000
6 months earlier. Payment of "P". It's value 1/2 year later is P(1+0.03)
6 months earlier. Payment of "P". It's value 1 year later is P(1+0.03)^2
6 months earlier. Payment of "P". It's value 1½ years later is P(1+0.03)^3
6 months earlier. Payment of "P". It's value 2 years later is P(1+0.03)^4
</span><span>We need to recognize these patterns. Similarly, we can identify the accumulated value of all 50 payments of "P". Starting from the last payment normally is most clear.
</span>
<span>P(1.03) + P(1.03)^2 + P(1.03)^3 + ... + P(1.03)^50
That needs to make sense. After that, it's an algebra problem.
P[(1.03) + (1.03)^2 + (1.03)^3 + ... + (1.03)^50]
</span>
P(<span><span>1.03−<span>1.03^51)/(</span></span><span>1−1.03) </span></span>= <span>250000</span>
