21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
Tasha's mistake is in Step 4
she has a negative sign in front of the fraction and she has a negative exponent on the 4 in the denominator
Answer:
The third model
Step-by-step explanation:
I'm pretty sure it is, I can't see all of them tho
Answer: 22 degrees
Step-by-step explanation:
Since the angle 180° is in the third quadrant, subtract 180° from 202°.
Answer:
The diameter of the circle is 22 units.
Step-by-step explanation:
x² + y² - 16x + 12y = 21 I graphed this equation on the graph below.
If this answer is correct, please make me Brainliest!
