Quadratic formula is x=(-b+-sqrt(b^2-4ac))/(2a)
a= 1, b=-4, and c=3
Therefore, x=(-(-4)+-sqrt((-4)^2-4(1)(3))/(2(1))
Solve for both the plus and minus equations; the answers will be the roots to the quadratic equation.
Answer:
Step-by-step explanation:
2x = 3y + 1/2
standard : Ax + By = C
2x = 3y + 1/2....multiply everything by 2 to get rid of the fractions
4x = 6y + 1 ....subtract 6y from both sides
4x - 6y = 1 <==
slope intercept : y = mx + b
2x = 3y + 1/2....subtract 1/2 from both sides
2x - 1/2 = 3y....divide everything by 3
2/3x - 1/6 = y...rearrange
y = 2/3x - 1/6 <===
Answer:
The solution region is x < –5 and x > 2
Step-by-step explanation:
We are given the inequalities, 2x–2 < –12 or 2x+3 > 7
Upon simplifying the inequalities, we get,
A. 
i.e. 
i.e. 
B. 
i.e. 
i.e. 
So, we get the solution is 
or 
and the plotted region can be seen below.
Answer:
No solutions
Step-by-step explanation:
i did this via substitution so i hope it isn't a problem
3x+y=4
6x+2y=−4
Step: Solve 3x+y=4for y:
3x+y+−3x=4+−3x(Add -3x to both sides)
y=−3x+4
Step: Substitute−3x+4foryin6x+2y=−4:
6x+2y=−4
6x+2(−3x+4)=−4
8=−4(Simplify both sides of the equation)
8+−8=−4+−8(Add -8 to both sides)
0=−12
so there are no solutions
hope this helps!!
