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MrRissso [65]
3 years ago
13

Will give brainliest to person who answers first. Much appreciated:)

Mathematics
2 answers:
pashok25 [27]3 years ago
7 0
First one i think is A.
Second one is True i believe
IRISSAK [1]3 years ago
4 0
1. i believe A Or D
2. False
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What does this description reveal about Lucia
GrogVix [38]

Answer:

it's the answer A

Step-by-step explanation:

becAuse she is scared / nerv

5 0
3 years ago
Read 2 more answers
9 × a number is 4500. what is the number?
oee [108]
We can write the equation 9x=4500

Now we just solve for x by dividing both sides by 9 to get:
x=500 

Hope this helps!
3 0
2 years ago
Read 2 more answers
When will the equation p(b)=520(0.88)^b have a value less than 100?
yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × 0.88^{b} to have a value less than 100 we can establish inequality as:

                     p(b) < 100

         or,  520 × 0.88^{b} < 100

         or, \frac{520}{520} × 0.88^{b} < \frac{100}{520}

         or, 0.88^{b} < \frac{1}{5.2}

         or, ㏒ ( 0.88^{b} ) < ㏒  (\frac{1}{5.2})

         or, b× ㏒ 0.88 < ㏒  (\frac{1}{5.2})

         or,  \frac{log (\frac{1}{5.2}) }{log (0.88)}   <  b

         or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

3 0
3 years ago
1/3 of students at a school are boys. If there are 600 students at the school, how many are girls?
Temka [501]

Answer:

200 students are boys and rest of 400 are girls

Step-by-step explanation:

Given that:

Total students = 300

1/3 students of total are boys

so.

Boys = 1/3(600)

Boys = 200

For finding number of girls:

Girls = total - boys

Girls = 600 - 200

Girls = 400

i hope it will help you!

8 0
3 years ago
Read 2 more answers
Consider the roots of a cubic equation with integral coefficients: −1, −4, and 3. Which choice is a factor of the cubic equation
mash [69]

Answer:

D

Step-by-step explanation:

Lets go case by case.

Given the roots, a factor will be part of the equation if for some of the roots the factor becomes null, i.e., equal to 0.

Is there any root that makes (x+3)=0? No, as it only becomes 0 for x = - 3 and -3 is not a root. So A NO!

Is there a root that makes (x-1)=0? No, as it only becomes 0 for x=1 and 1 is not a root. So B NO!

(x-4)=0 only for x=4, and as 4 is not a root, C NO!

The last, (x-3)=0 if x=3. As 3 is one of the roots, (x-3) is a factor of our equation!

D is the only correct option!

5 0
2 years ago
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