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Anettt [7]
4 years ago
12

Please help me on this question 92x3 A. 79 B.42 C.276 D.267

Mathematics
1 answer:
victus00 [196]4 years ago
8 0
The correct answer is
C.276
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Law of Sines or Law of Cosines....Help!!
iren2701 [21]

Answer:

Law of cosines to find missing measures

c^2= a^2+ b^2 - 2ab*cos(C)

Used because it is a SAS triangle

Step-by-step explanation:

This is known as a side, angle, side, or SAS triangle. We can find the missing measures by using the Law of cosines

c^2= a^2+b^2-2ab*cos(C)

7 0
3 years ago
Im struggling how do I do this practice assignment? (Photo added)
olga_2 [115]

Answer:

Step-by-step explanation:

I can't see the pic but I would be glad to help you.

6 0
3 years ago
If 81 is added to a number the result is 39 less than three times the number
Deffense [45]

let x =the number

Step-by-step explanation:

81+x=3x-39

group like terms

81+39=3x-x

120=2x

120/2=2x/2

60=x

therefore x =60

4 0
3 years ago
Read 2 more answers
The question is Fiona's swimming pool is a right rectangular prism. It holds 137 1/2 cubic feet of water. The length of the pool
cricket20 [7]

Answer:

The width is 4 feet

Step-by-step explanation:

Yes, I might be able to answer it! Hello there!

In this question, we are asked to calculate the height of a pool which has a shape of right rectangular prism.

The key to solving this problem is simply by knowing the formula for the volume of a right rectangular prism.

Mathematically the volume V is w * h * l where w , h and l are the width, height and length respectively.

Now let’s input these values and get what the height of the pool is.

It would be easier if you had the measurements are in decimals;

137 1/2 becomes 137.5

6 1/4 becomes 6.25

5 1/2 becomes 5.5

kindly note the fraction 1/2 is 0.5 in decimals while the fraction 1/4 is 0.25 in decimals

So now let’s compute the height;

137.5 = w * 6.25 * 5.5

w = 137.5/(6.25 * 5.5)

w = 137.5/(34.375)

w = 4 feet

8 0
3 years ago
Element X decays radioactively with a half life of 13 minutes. If there are 530 grams of Element X, how long, to the nearest ten
Leona [35]

Answer:

t \approx 50.4\,min

Step-by-step explanation:

The time constant of the element X is:

\tau = \frac{13\,min}{\ln 2}

\tau = 18.755\,min

The decay function has the following form:

\frac{m}{m_{o}} = e^{-\frac{t}{\tau} }

t = -\tau \cdot \ln \frac{m}{m_{o}}

t = -(13\,min)\cdot \ln \left(\frac{11\,g}{530\,g} \right)

t \approx 50.4\,min

6 0
3 years ago
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