Answer:
t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490
Step-by-step explanation:
Solve for t:
4.9 t^2 - 2.78 t - 1.15 = 0
4.9 t^2 - 2.78 t - 1.15 = (49 t^2)/10 - (139 t)/50 - 23/20:
(49 t^2)/10 - (139 t)/50 - 23/20 = 0
Multiply both sides by 10/49:
t^2 - (139 t)/245 - 23/98 = 0
Add 23/98 to both sides:
t^2 - (139 t)/245 = 23/98
Add 19321/240100 to both sides:
t^2 - (139 t)/245 + 19321/240100 = 75671/240100
Write the left hand side as a square:
(t - 139/490)^2 = 75671/240100
Take the square root of both sides:
t - 139/490 = sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490
Add 139/490 to both sides:
t = 139/490 + sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490
Add 139/490 to both sides:
Answer: t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490
The answer is 20 I believe
Answer:
x = -4, 5/2
Step-by-step explanation:
A quadratic can be solved may ways, including graphing, factoring, and the quadratic formula. You can also check possible answers by making use of the relationships between solutions and the coefficients.
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A graph is attached. It shows the solutions to be -4 and 5/2.
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When factored, the equation becomes ...
(2x -5)(x +4) = 0 . . . . . has solutions x=-4, x=5/2 (these make the factors zero)
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Using the quadratic formula, the solutions of ax^2 +bx +c = 0 are found from ...
x = (-b±√(b²-4ac))/(2a)
x = (-3±√(3²-4(2)(-20))/(2(2)) = (-3±√169)/4 = {-16, +10}/4
x = {-4, 5/2}
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For ax^2 +bx +c = 0, the solutions must satisfy ...
product of solutions is c/a = -20/2 = -10
Only the first and last choices have this product.
sum of solutions is -b/a = -3/2
Only the first choice (-4, 5/2) has this sum.
An object weighs 140 pounds more on Jupiter than it weighs on Venus. By simple algebraic operations, the required value is calculated.
<h3>What are the algebraic operations?</h3>
Addition, subtraction, multiplication, and division are the basic algebraic operations that are used for many computations.
<h3>Calculation:</h3>
It is given that,
An object's weight on Venus is approximately 9/10 of its weight on earth. I.e., WV = 9/10 WE
An object's weight on Jupiter is approximately 23/10 of its weight on earth. I.e., WJ = 23/10 WE
If an object weighs 100 pounds on earth, then
The weight of the object on Venus is
WV = 9/10 × 100 = 90 pounds
The weight of the object on Jupiter is
WJ = 23/10 × 100 = 230
Thus, the difference between them is 230 - 90 = 140 pounds.
So, the object weighs 140 pounds more on Jupiter than on Venus.
Learn more about algebraic operations here:
brainly.com/question/24935016
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Answer:
its the last choice
Step-by-step explanation:
