Which of the following is an example of a function

Mathematics

1 answer:

kicyunya [14]3 years ago

6 0

Answer: Option C.

Step-by-step explanation:

A function goes trough the x-axis when f(x) = 0 for some value of x.

For example, when we say that a quadratic function has no real zeros, this means that the determinant is less than zero, so the roots of the equation:

a*x^2 + b*x + c = 0

are complex roots, this means that for the function:

f(x) = y = a*x^2 + b*x + c

there is not a real number x such f(x) = 0

So the correct option is C.

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Gala2k [10]

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3 years ago

A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title

kirill [66]

$y' = \frac{dy}{dx}$

seperable differential equations will have the form
$\frac{dy}{dx} = F(x) G(y)$

what you do from here is isolate all the y terms on one side and all the X terms on the other
$\frac{dy}{G(y)} = F(x) dx$
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
$\int \frac{1}{G(y)} dy = \int F(x) dx

$

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it

In your problem,
$G(y) = \sqrt{1-y^2}

F(x) = 2x$

so all you need to integrate is
$\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx$