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marissa [1.9K]
3 years ago
13

Which of the following is an example of a function

Mathematics
1 answer:
kicyunya [14]3 years ago
6 0

Answer: Option C.

Step-by-step explanation:

A function goes trough the x-axis when f(x) = 0 for some value of x.

For example, when we say that a quadratic function has no real zeros, this means that the determinant is less than zero, so the roots of the equation:

a*x^2 + b*x + c = 0

are complex roots, this means that for the function:

f(x) = y = a*x^2 + b*x + c

there is not a real number x such f(x) = 0

So the correct option is C.

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You need 150g of flour for 12 cakes, how much flour do you need for 30 cakes?
Bogdan [553]
150 g flour for 12 cakes
x g flour for 30 cakes
x = (150 x 30) : 12 = 375 g of flour

another method:

150 flour for 12 cakes
??? for 30 cakes

30 : 12 = 2.5
150 x 2.5 = 375 g flour


5 0
3 years ago
Read 2 more answers
The sum of two The perimeter of a rectangle is 30cm. If the length is 3 cm longer than the width, find
Llana [10]

Answer:

Width: 6 cm

Length: 9 cm

Step-by-step explanation:

Width: x

Length: x + 3

2(x)+2(x+3) = 30cm

2x + 2x + 6 = 30

4x = 30-6

x = 24/4

x = 6

4 0
3 years ago
Which unit rate is higher 24 for 5 or 5 for 24
frez [133]

Answer:

24 for 5 is higher because you have to divide 24 by 5 and if you do that it gives you $4.8, while 5 for 24 gives you a unit rate of $0.20.

3 0
3 years ago
Question is attached below, Good Luck! I will Mark Brainliest for best answer!
DerKrebs [107]

Answer:

1960 cm^2

Step-by-step explanation:

Surface area:

Area of cross section x 2 = 1/2 x 20 x 21 x 2 = 420 cm^2

Area of slope = 29 x 22 = 638cm^2

Area of base = 22 x 20 = 440cm^2

Area of back = 21 x 22 = 462cm^2

Total Surface area = 462+440+638+420 = 1960cm^2

Hope this helps

6 0
3 years ago
Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo
Ilya [14]

Answer:

x^6+3x^3+3+\dfrac{1}{x^3}

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}

4 0
3 years ago
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