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SIZIF [17.4K]
3 years ago
14

HELP PLEASE

Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0

Answer:

6.08 ft

Step-by-step explanation:

Volume of cone = \frac{1}{3}\pir²h

Radius = \sqrt{ \frac{V}{\frac{1}{3}\pi h  } }

R = \sqrt{\frac{376.8}{\frac{1}{3} \pi 10} }

R = \sqrt{\frac{376.8}{10.47} }

R = \sqrt{36.98}

R = 6.08

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\int\limits^0_\pi {x*sin^{m} (x)} \, dx
Ket [755]

Let

I(m) = \displaystyle \int_0^\pi x\sin^m(x)\,\mathrm dx

Integrate by parts, taking

<em>u</em> = <em>x</em>   ==>   d<em>u</em> = d<em>x</em>

d<em>v</em> = sin<em>ᵐ </em>(<em>x</em>) d<em>x</em>   ==>   <em>v</em> = ∫ sin<em>ᵐ </em>(<em>x</em>) d<em>x</em>

so that

I(m) = \displaystyle uv\bigg|_{x=0}^{x=\pi} - \int_0^\pi v\,\mathrm du = -\int_0^\pi \sin^m(x)\,\mathrm dx

There is a well-known power reduction formula for this integral. If you want to derive it for yourself, consider the cases where <em>m</em> is even or where <em>m</em> is odd.

If <em>m</em> is even, then <em>m</em> = 2<em>k</em> for some integer <em>k</em>, and we have

\sin^m(x) = \sin^{2k}(x) = \left(\sin^2(x)\right)^k = \left(\dfrac{1-\cos(2x)}2\right)^k

Expand the binomial, then use the half-angle identity

\cos^2(x)=\dfrac{1+\cos(2x)}2

as needed. The resulting integral can get messy for large <em>m</em> (or <em>k</em>).

If <em>m</em> is odd, then <em>m</em> = 2<em>k</em> + 1 for some integer <em>k</em>, and so

\sin^m(x) = \sin(x)\sin^{2k}(x) = \sin(x)\left(\sin^2(x)\right)^k = \sin(x)\left(1-\cos^2(x)\right)^k

and then substitute <em>u</em> = cos(<em>x</em>) and d<em>u</em> = -sin(<em>x</em>) d<em>x</em>, so that

I(2k+1) = \displaystyle -\int_0^\pi\sin(x)\left(1-\cos^2(x)\right)^k = \int_1^{-1}(1-u^2)^k\,\mathrm du = -\int_{-1}^1(1-u^2)^k\,\mathrm du

Expand the binomial, and so on.

8 0
3 years ago
PLEASE HELP
mr Goodwill [35]

If 3 ft = 1yard

?        = 16 yards?

Thats \frac{16 yards * 3ft}{1yard}

The common values cancel each other out and you'll have 48 feet :)

3 0
2 years ago
Is 0.09 greater than 0.7
chubhunter [2.5K]
No, 0.7 is greater than 0.09

0.70 > 0.09

hope this helps
3 0
4 years ago
Read 2 more answers
1/9,1/3,5/9 find the rule
anastassius [24]
It’s going up by 2/9 . if you did it for the first one it’d b 3/9 which is 1/3
3 0
3 years ago
What are the zero(s) of the function f(x)=4x2-36x over x-9?
vfiekz [6]
F(x) = (4x^2 - 36x) / (x-9)
0 = 4x * (x-9) / (x-9)
0 = 4x

x=0
hope this helps
7 0
3 years ago
Read 2 more answers
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