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arlik [135]
2 years ago
12

A lending institution supplied the following data on loan approvals by four loan officers. Use α = .05 and test to determine whe

ther the loan approval decision is associated with the loan officer reviewing the loan application.
Loan Approval Decision
Loan Officer Approved Rejected
Miller 24 16
McMahon 17 13
Lee 35 15
Sanchez 11 9

Mathematics
1 answer:
bija089 [108]2 years ago
5 0

Answer:

As chi^2 < 7.815, and P > 0.05, we do not reject null hypothesis.

         

Thus, there is no significant evidence that the loan approval decision is not independent of the loan officer reviewing the loan application.

Step-by-step explanation:

Find the given attachment

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Masteriza [31]

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Step-by-step explanation:

There are always 180 degrees so you subtract the 2 others and you get the angle (60+40-180)

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A ball rolled from Point A to Point B in 18 second at a speed of 14 m/s. IT took another 18 seconds to roll form Pint B to Pint
vaieri [72.5K]

Answer:

d=252m, u dint put the speed it was rolling at from point B to C so I could only solve for A to B. However if you use the formula below you can find the distance from B to C and add that to A to B giving the total distance rolled.

Step-by-step explanation:

d=vt

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Is there anyone that can help me with this problem?
saul85 [17]

Answer:

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Step-by-step explanation:

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2 years ago
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Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer
Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

0=(3x+2)(x-4)

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply (3x+2)(x-4) i.e. 3x^2-12x+2x-8 = 3x^2-10x-8

So, the equation becomes:

0=3x^2-10x-8

Comparing this equation to standard quadratic equation:

ax^2+bx+c=0

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}

The answer is same from both the approaches.

So, the correct answer is:

C) Both

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2 years ago
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