Answer:
The correct answer is : DCQ ( angle) = DCE (angle)
Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.
To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:
p '(t) = 2t + 5 = 0
Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.
( divisor / dividend ) does not go into the same Evenly
Answer:
Step-by-step explanation:
<u>Given points</u>
<u>Slope-intercept form</u>
<u>Slope of the line is</u>
- m = (6a - 2a)/( -5a - a) = 4a/(-6a) = - 2/3
<u>The y-intercept is:</u>
- 2a = -2/3*a + b
- b = 2a + 2/3a
- b= 8/3a
<u>So the line is:</u>
<span>As far as i know it is related to Gauss.
Write the sequences forward and backward first.
1 +2 +3 +.....+1002
1002+1001+1000+.....+1
--------------------------------------... Adding them
1003+1003+......(1002 times)
=1002x1003
But this contains the series twice.
So, the sum is = 1002x1003/2=501x1003=502503. answer</span>