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3 years ago

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Mathematics

1 answer:

enot [183]3 years ago

8 0

Answer:

the second option

y = (-1/2)x + 11

Step-by-step explanation:

x = 2

y = (-1/2)×2 + 11 = -1 + 11 = 10

the same as the table.

x = 4

y = (-1/2)×4 + 11 = -2 + 11 = 9

the same as the table.

x = 6

y = -3 + 11 = 8

the same as the table.

x = 8

y = -4 + 11 = 7

the same as the table.

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Evaluate (98 x 102) by using suitable identities.

GREYUIT [131]

Answer:

The answer is 9996

Step-by-step explanation:

Using the identity (x+a)(x+b) = x ^2 +(a+b)x+ab

Writing 102 as 100+2 and 98 as 100−2

Hence (100+2)(100−2) = 100 ^2 +[2+(−2)]100+(2)(−2)

= 10000+(0)100−4

= 9996

The answer is 9996

8 0

3 years ago

Read 2 more answers

If f(1) = 6 and f(n) = f(n − 1) +3, then f(7) = (1) 10 (2) 24 (3) 15 (4) 18

Juliette [100K]

Answer:

Step-by-step explanation:

f(n) = f(n − 1) + 3

if n = 7 => f(7) = f(7-1) + 3 = f(6) + 3

if n = 6 => f(6) = f(6-1) + 3 = f(5) + 3

if n = 5 => f(5) = f(5-1) + 3 = f(4) + 3

if n = 4 => f(4) = f(4-1) + 3 = f(3) + 3

if n = 3 => f(3) = f(3-1) + 3 = f(2) + 3

if n = 2 => f(2) = f(2-1) + 3 = f(1) + 3

if f(1) = 6 then f(2) = 9

f(3) = 12

f(4) = 15

f(5) = 18

f(6) = 21

f(7) = 24

3 0

3 years ago

the distance d a train travela varies directly with the amount of time t that has elapse since departure. If the train travela 4

antiseptic1488 [7]

475/9.5 x4 = 200miles in 4hrs

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3 years ago

On a shelf at a gaming store, there are five Sony Playstations and three Nintendo Wii consoles left. If one gaming system is sel

Tpy6a [65]

Step-by-step explanation:

a probability is always desired cases over total possible cases.

so, we have actually 8 systems (5 + 3) we can pick from.

therefore, the total possible cases are 8.

the desired case is in this question to pick one of the 3 Wii consoles.

the probability to pick a Wii is therefore

3/8 = 0.375

5 0

2 years ago

Read 2 more answers

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

Find the value of y

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

Find the values of x

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

4 years ago