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Alchen [17]
2 years ago
5

The diagram shows a regular dodecagon.Work out the size of one interior angle

Mathematics
1 answer:
nikdorinn [45]2 years ago
5 0

Answer:

150°

Step-by-step explanation:

number of terms=12

sum of exterior angles=360

one exterior angle=360/12=30

interior angle=180-30=150°

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Help please!!!!!!!! It’s pre cal
tino4ka555 [31]

Answer:

No, the inverse function does not pass the vertical line test.

Step-by-step explanation:

Remember that h(x)=y. To find the inverse of our function we are going to invert x and y and solve for y:

h(x)=x^2+3

y=x^2+3

x=y^2+3

x-3=y^2

y=\pm\sqrt{x-3}

h^{-1}(x)=\pm\sqrt{x-3}

Now we can graph our function an perform the vertical line test (check the attached picture).

Remember that the vertical line test is a visual way of determine if a relation is a function. A relation is a function if and only if it only has one value of y for each value of x. In other words, a relation is a function if a vertical line only intercepts the graph of the function once.

As you can see in the picture, the vertical line x = 15 intercepts the function twice, so the inverse function h(x) is not a function.

We can conclude that the correct answer is: No, the inverse function does not pass the vertical line test.

6 0
3 years ago
Read 2 more answers
How many significant numbers in 34.6209
JulijaS [17]

Answer:

6

Step-by-step explanation:

5 0
2 years ago
I NEED HELP ASAP Use the Law of Detachment or the Law of Syllogism to draw a conclusion. 3. If Shauna is early for her meeting,
yuradex [85]
W = Shauna wakes up early
M = Shauna is early for her Meeting
P = Shauna gains a promotion

1. M -> P
2. W -> M
3. W
: . P
6 0
3 years ago
3a+4b= c solve for b
Alina [70]

Answer:

b = (c - 3a)/4

Step-by-step explanation:

3a + 4b = c

4b = c - 3a

b = (c - 3a)/4

6 0
2 years ago
The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th
Fantom [35]

Answer:

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C

Step-by-step explanation:

To find:

∫6x^5(x^6-2)\,dx

Solution:

Method of substitution:

Let x^6-2=t

Differentiate both sides with respect to t

6x^5\,dx=dt

[use (x^n)'=nx^{n-1}]

So,

∫6x^5(x^6-2)\,dx = ∫ t\,dt = \frac{t^2}{2}+C_1 where C_1 is a variable.

(Use ∫t^n\,dt=\frac{t^{n+1} }{n+1} )

Put t=x^6-2

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1

Use (a-b)^2=a^2+b^2-2ab

So,

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C

where C=2+C_1

Without using substitution:

∫6x^5(x^6-2)\,dx = ∫6x^{11}-12x^5\,dx = \frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C

So, same answer is obtained in both the cases.

7 0
2 years ago
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