There are 20 balls in a bag. Ten of the balls are red, 4 are green, and the rest are yellow.

V<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2A%202%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="\frac{3}{4} * 2

myrzilka [38]

Answer:

$1\frac{3}{4}$

Step-by-step explanation:

In order to find the answer, you first need to convert the mixed number (2 1/3) into a improper fraction and then multiply.

$\frac{3}{4} \times2\frac{1}{3}$

$2\frac{1}{3} =3\times2=6+1=7=\frac{7}{3}$

$\frac{3}{4} \times\frac{7}{3}$

$3\times7=21$

$4\times3=12$

$=\frac{21}{12} =\frac{7}{4} =1\frac{3}{4}$

$=1\frac{3}{4}$

Hope this helps.

7 0

2 years ago

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((

neonofarm [45]

Answer:

2/5 or .4

Step-by-step explanation:

basically look at the points where the line meets the graph. two points would be 0,20 and 50,40. then count the amount that it changes vertically and then horizontally. +20vertical +50 horizonal giving the slope 20/50. this can then be simplified to 2/5 or the equivalent number .4

8 0

2 years ago

Read 2 more answers

Could you help me understand cross sections of three-dimenstional object its harder than it sound.

umka21 [38]

A section, or cross-section, is a view of a 3-dimensional object from the position of a plane through the object. A section is a common method of depicting the internal arrangement of a 3-dimensional object in two dimensions. It is often used in technical drawing and is traditionally crosshatched.

Cross sections of three-dimensional objects are two-dimensional shapes of various sizes. They may be parallel to a side or base of the object or at an angle to these surfaces. A cross section may resemble the shape of the object’s side or base, or it may have a completely different shape.

5 0

2 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$