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Irina-Kira [14]
3 years ago
9

1.36 as a fraction help

Mathematics
2 answers:
iogann1982 [59]3 years ago
7 0

Answer: 34/25

Step-by-step explanation:

(136÷4)(100÷4) = 34/25 when reduced to the simplest form. As the numerator is greater than the denominator, we have an IMPROPER fraction,

kipiarov [429]3 years ago
3 0

Answer:

The answer is 1 \frac{9}{25}

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An aquarium 2 m long, 1 m wide, and 1 m deep is full of water. Find the work needed to pump half of the water out of the aquariu
loris [4]

Answer:

Workdone = 2450Joules

Step-by-step explanation:

Let the top of the aquarium be at height 0.

Let the bottom of the aquarium be at height 1

F = mg = 2p◇x × g

F= 2000◇x × 9.8

F = 19600◇x

Workdone = 19600xdx

Total workdone = Integral (limits 0.5 -0)19600×dx

Total work = [9800x^2]^0.5

Total work= 9800× 0.5^2 = 2450 Joules

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2 years ago
Which conversions from scientific notation to standard notation are true? Check all that apply.
avanturin [10]

Step-by-step explanation:

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2 years ago
Is the given ordered pair a solution to the equation? <br><br><br> y=2x+7;(-2, 3)
iren2701 [21]

Answer:

The answer to your question is: Yes, it is a solution

Step-by-step explanation:

           

Point  (-2, 3)

                         Line:            y = 2x + 7

Process, replace the point in the line

                                          3 = 2(-2) + 7

                                          3 = -4 + 7

                                          3 = 3

As we got that 3 equals 3, then the point given is a solution of the equation.

               

5 0
3 years ago
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

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Answer:

1a) −24x^4−52x^3+198x^2+126x−325

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