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blsea [12.9K]
3 years ago
11

Please help me with math, it’s easy!! explanation needed!

Mathematics
1 answer:
Olenka [21]3 years ago
3 0

Answer:

  0

Step-by-step explanation:

This equation is in "vertex form," meaning that you can identify the vertex and other features of the graph from the equation.

  y = a(x -h)² +k . . . . . the vertex is (h, k); the vertical scale factor is "a"

Comparing to your equation, you see ...

  a = -1/2, h = 3, k = -1

The vertex is (h, k) = (3, -1). The vertical scale factor is negative.

__

This tells you the graph opens downward (the scale factor is negative), and the vertex (maximum point) is below the x-axis. (It has a negative y-coordinate.)

Because it start below the x-axis and goes down from there, the graph does not intersect the x-axis. There are zero (0) x-intercepts.

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-18.3 = b + -8.3<br> b =
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Answer:

Here,

-18.3=b+ -8.3

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A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

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Answer:

see below

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-2x-5y=30

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To find the y intercept, set x =0 and solve for y

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3 years ago
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