A line that perpendicular to the line y= 2/3x + 4 and goes through the point (-2,5)
1 answer:
step 1
Find the slope of the given line
we have
y=(2/3)x+4
the slope is m=2/3
Remember that
If two lines are perpendicular, then their slopes are opposite reciprocal
so
the slope of the perpendicular line to the given line is
m=-3/2
step 2
Find the equation of the line in slope intercept form
y=mx+b
we have
m=-3/2
point (-2,5)
substitute
5=(-3/2)(-2)+b
solve for b
5=3+b
b=2
therefore
<h2>y=-(3/2)x+2</h2>
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