Answer:
If line EF was dilated by a scale of 1/2 from the origin to get line E'F', then if line E'F' is dilated by a scale of 2 from the origin, EF is obtained. Also, the length of EF is double than the length of E'F'.
Dilation by a scale of 2 from the origin transforms point (x,y) into (2*x, 2*y)
E'(1,0) -> E(2,0)
F'(1, 3) ->F(2, 6)
length of E'F': 3
length of EF: 6
To solve, set an equation:
First Number: x
Second Number: 2x
x+2x=36
3x=36
divide both sides by 3
x=13
First Number: (x) 12
Second Number: (2x) 24
Answers: 12 and 24
Answer:
x = 22
Step-by-step explanation:
x-10=12
We want to solve for x
Add 10 to each side
x-10+10=12+10
x = 22
If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
Learn more about half life here
brainly.com/question/4318844
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The area of a circle is given by the formula:
A =

r^2
Since

= 3.14, and r = 6, sub these values into the equation,
A = 3.14 x 6^2
= 113.04
Hope this helped!