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nexus9112 [7]
3 years ago
7

A pendulum on a planet, where gravitational acceleration is unknown, oscillates with a time period 5 sec. If the mass is increas

ed six times, what is the time period of the pendulum?
Physics
1 answer:
olchik [2.2K]3 years ago
8 0

Explanation:

We have, a pendulum on a planet, oscillates with a time period 5 sec. The formula used to find the time period is given by :

T=2\pi \sqrt{\dfrac{l}{g}}

l is length of the pendulum

g is acceleration due to gravity on which it is placed

It is clear that, the time period of pendulum is independent of the mass. Hence, if the mass is increased six times, its time period remains the same.

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Ranking Task: The Electromagnetic Spectrum
shutvik [7]

The increasing order of the wavelength from left to right are as follows Gamma Rays <  X-rays < UV rays < visible rays < infrared rays < microwaves < radio waves.

The electromagnetic spectrum consists of many waves which are made up of electric field and the magnetic field.

It is said that the electromagnetic wave behaves like particle as well as the wave.

The particle like pieces of the wave are called photons which contains the energy of the wave and the electromagnetic waves are primarily decided by the wavelength and the frequency of the wave.

The group of electromagnetic waves are known as electromagnetic spectrum.

The electromagnetic wave in the order of increasing wavelength are Gamma Rays <  X-rays < UV rays < visible rays < infrared rays < microwaves < radio waves.

To know more about electromagnetic spectrum, visit,

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8 0
1 year ago
If the western component of the wind is half of the south, what is the angle of the wind with the south?
den301095 [7]

Answer:

This above a triangle that models our situation.

Explanation:

We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.

Let the component that travel in the south be the length of a.

According to the problem, the westard component is half of that so let that length be a/2.

Now we must find the angle of the wind in the South.

This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

\tan(x)  =  \frac{opp}{adj}

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have

\tan(x)  =  \frac{ -  \frac{a}{2} }{ - a}

\tan(x)  =  -  \frac{a}{2}  \times  -  \frac{1}{a}  =  \frac{1}{2}

Now we take the arctan or inverse tan of 1/2.

\tan {}^{ - 1} ( \frac{1}{2} )  = 26.57

3 0
2 years ago
Read 2 more answers
The chemical and physical actions of groundwater form
miv72 [106K]
The chemical and physical actions of groundwater form Karst topography. It is <span>any region where the terrain has been dissolved by the physical and chemical weathering of the bedrock. 
There is no reason why glaciers, volcanoes, and mountains should be formed as a result of these actions. </span>
5 0
4 years ago
Read 2 more answers
-Para lograr que una pieza de 0,300 kg de cierto metal aumente su temperatura desde 40°C a 60 °C ha sido necesario suministrarle
marishachu [46]

Answer:

parte a) el calor específico es c = 0.383 J /(gr*K)

parte b) la temperatura inicial es T inicial= 52.72 °C

Explanation:

para el primer punto la formula para el calor Q es:

Q = m * c * ( T final - T inicial )

donde

m= masa de la pieza = 0.300 kg = 300 gr

Q = flujo de energía en forma de calor= 2299 J

c = calor específico

T final = temperatura final =40°C

T inicial = temperatura inicial = 60 °C

entonces

Q = m * c * ( T final - T inicial )

c = Q / [ m* ( T final - T inicial ) = 2299 J/[ 300 gr  * ( 60 °C - 40°C )]

= 0.383 J /(gr*K)

c = 0.383 J /(gr*K)

para el segundo punto usamos la misma formula

Q = m * c * ( T final - T inicial )

pero

m= 200 gr= 0.200 kg

c=459.8 J/(kg*K) , Q =20.900 J , T final = 280 °C

Q = m * c * ( T final - T inicial )

T inicial = T final - Q/(m*c)  =280 °C - 20.900 J/(459.8 J/(kg*K)* 0.200 kg) = 52.72 °C

7 0
4 years ago
A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
AfilCa [17]
First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)
3 0
3 years ago
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