An uncovered pot of soup is simmering on a stove, and there are water droplets on the wall above the back of the stove. what seq
2 answers:
<u>Answer:</u> At first, vaporization will occur then condensation will occur.
<u>Explanation:</u>
Vaporization is defined as a physical process in which liquid starts getting converted to the vapor (gaseous) state.
Condensation is defined as a physical process in which gas starts getting converted to liquid state.
When an uncovered pot on the soup is simmering on the stove, vapor formation starts and liquid starts to get convert into vapors and when these vapors reaches the cold surface on the wall, it starts to condense and gets converted into liquid phase again.
Hence, at first, vaporization process will occur then condensation process will occur.
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Answer:
given,
speed of the car = 20 m/s
final speed of car = 0 m/s
distance between car and the deer = 38 m
reaction time, t = 0.5 s
deceleration of the car = 10 m/s².
a) distance between deer and car
distance travel in the reaction time
d₁ = v x t
d₁ = 20 x 0.5 = 10 m
distance travel after you apply brake
using equation of motion
v² = u² + 2 a s
0 = 20² - 2 x 10 x s
s = 20 m
total distance traveled by the car
D = d₁ + d₂
D = 20 + 10 = 30 m
distance between car and the deer = 38 m - 30 m
= 8 m
b) now, maximum speed car.
distance travel in reaction time
d₁ = s x t
d₁ = 0.5 V
distance left between them
d₂ = 38 - d₁
d₂ = 38 - 0.5 V
distance travel after you apply brake
using equation of motion
v² = u² + 2 a d₂
0 = (V)² - 2 x 10 x (38 - 0.5 V)
V² + 10 V - 760 = 0
now, solving the quadratic equation
V = 23.01 , -33.01
rejecting the negative term.
hence, maximum speed of the car could be V = 23.01 m/s