An uncovered pot of soup is simmering on a stove, and there are water droplets on the wall above the back of the stove. what seq
2 answers:
<u>Answer:</u> At first, vaporization will occur then condensation will occur.
<u>Explanation:</u>
Vaporization is defined as a physical process in which liquid starts getting converted to the vapor (gaseous) state.
Condensation is defined as a physical process in which gas starts getting converted to liquid state.
When an uncovered pot on the soup is simmering on the stove, vapor formation starts and liquid starts to get convert into vapors and when these vapors reaches the cold surface on the wall, it starts to condense and gets converted into liquid phase again.
Hence, at first, vaporization process will occur then condensation process will occur.
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Answer:
t = 0.0735 m
Explanation:
Angular acceleration of the flywheel is given as
now after t = 8 s the speed of the flywheel is given as
now rotational kinetic energy of the wheel is given as
now we have
Refer to the diagram shown below.
Assume that
(a) The piano rolls down on frictionless wheels,
(b) Wind resistance is negligible.
The distance along the ramp is
d = (1.3 m)/sin(22°) = 3.4703 m
The component of the piano's weight along the ramp is
mg sin(22°)
If the acceleration down the ramp is a, then
ma = mg sin(22°)
a = g sin(22°) = (9.8 m/s²) sin(22°) = 3.671 m/s²
The time, t, to travel down the ramp from rest is given by
(3.4703 m) = 0.5*(3.671 m/s²)*(t s)²
t² = 3.4703/1.8355 = 1.8907
t = 1.375 s
Answer: 1.375 s
Assume that
(a) The piano rolls down on frictionless wheels,
(b) Wind resistance is negligible.
The distance along the ramp is
d = (1.3 m)/sin(22°) = 3.4703 m
The component of the piano's weight along the ramp is
mg sin(22°)
If the acceleration down the ramp is a, then
ma = mg sin(22°)
a = g sin(22°) = (9.8 m/s²) sin(22°) = 3.671 m/s²
The time, t, to travel down the ramp from rest is given by
(3.4703 m) = 0.5*(3.671 m/s²)*(t s)²
t² = 3.4703/1.8355 = 1.8907
t = 1.375 s
Answer: 1.375 s