An uncovered pot of soup is simmering on a stove, and there are water droplets on the wall above the back of the stove. what seq
2 answers:
<u>Answer:</u> At first, vaporization will occur then condensation will occur.
<u>Explanation:</u>
Vaporization is defined as a physical process in which liquid starts getting converted to the vapor (gaseous) state.
Condensation is defined as a physical process in which gas starts getting converted to liquid state.
When an uncovered pot on the soup is simmering on the stove, vapor formation starts and liquid starts to get convert into vapors and when these vapors reaches the cold surface on the wall, it starts to condense and gets converted into liquid phase again.
Hence, at first, vaporization process will occur then condensation process will occur.
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Answer:
The moment of inertial of the wheel,
Explanation:
Given;
8 spokes of uniform diameter
mass of each spoke, =
length of each spoke, = L
mass of outer ring, =
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where;
is the moment of inertia of each spoke
is the moment of inertia of the rim
Moment of inertia of each spoke
Moment of inertial of the wheel
A) initial volume
We can calculate the initial volume of the gas by using the ideal gas law:
where
is the initial pressure of the gas
is the initial volume of the gas
is the number of moles
is the gas constant
is the initial temperature of the gas
By re-arranging this equation, we can find:
2) Now the gas cools down to a temperature of
while the pressure is kept constant:
, so we can use again the ideal gas law to find the new volume of the gas
3) In a process at constant pressure, the work done by the gas is equal to the product between the pressure and the difference of volume:
by using the data we found at point 1) and 2), we find
where the negative sign means the work is done by the surrounding on the gas.
We can calculate the initial volume of the gas by using the ideal gas law:
where
By re-arranging this equation, we can find
2) Now the gas cools down to a temperature of
while the pressure is kept constant:
3) In a process at constant pressure, the work done by the gas is equal to the product between the pressure and the difference of volume:
by using the data we found at point 1) and 2), we find
where the negative sign means the work is done by the surrounding on the gas.