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3 years ago

Which statement best describes what happens at the site of a divide?

Physics

2 answers:

olga55 [171]3 years ago

8 0

Answer:

Option (3)

Explanation:

A drainage divide is a high elevated ridge that separates two watershed or catchment basins. The water flows over the tributaries on both the side of the drainage divide and empties into the separate water bodies such as rivers and streams in the opposite directions.

When a huge mountain range forms a drainage divide, then it is termed as the dividing range.

The drainage divide is mainly divided into 3 types. They are as follows-

(1) Continental divides

(2) Major divides

(3) Minor divides.

Hence, the correct answer is option (3).

lilavasa [31]3 years ago

7 0

Answer:

C. Streams on each side of the divide flow in opposite directions.

Explanation:

Just took the assessment on edgenuit.

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denis-greek [22]

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4 years ago

Star a has an absolute magnitude of 8. what is its apparent magnitude at a distance of 100 pc

tresset_1 [31]

From the definition of apparent magnitude, we know that:
$m_{1} - m_{2} = -2.5Log( \frac{F_{1}}{F_{2}} )$
where:
m = apparent magnitude
F = corresponding flux

We also know that the flux is given by the formula:
$F = \frac{L}{4 \pi d^{2} }$
where:
L = luminosity
d = distance

Therefore:
$\frac{F_{1} }{F_{2}} = (\frac{L_{1} }{4 \pi d_{1}^{2} })(\frac{4 \pi d_{2}^{2} }{L_{2} }) \\ = \frac{L_{1}d_{2}^{2}}{L_{2}d_{1}^{2}}$

Now, let's apply these formulae to the same star (therefore, same luminosity), using apparent magnitude and absolute magnitude (which is defined as the apparent magnitude the star would have if it were at a distance of 10pc):
$m - M = 2.5 Log ( \frac{d}{10pc})^{2}$

Now, let's solve for m:
$m = M + 2.5 Log ( \frac{d}{10})^{2}$
= $8 + 2.5 Log ( \frac{100}{10})^{2}$ 
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Hence, the apparent magnitude of the star would be m = +13

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