<span>You are given the following statistics showing how many points each player scores on average and how many points the team scores in a game when the player is not playing.
Player A PPG: 25 Team Points
when the player is absent: 100
Player B PPG: 24 Team Points
when the player is absent: 80
Player C PPG: 20 Team Points
when the player is absent: 84
Player D PPG: 19 Team Points
when the player is absent: 87
Player E PPG: 13 Team Points
when the player is absent: 50
Player F PPG: 5 Team Points
when the player is absent: 99
Player G PPG: 5 Team Points
when the player is absent: 90
(1) The player that is most helpful to the team is Player A. When player A is playing,he can garner 25 points and when he is not around, the team loses 100 points.
(2) The player that is the most altruistic (helpful to others) is Player E. Even if he can just gain 13 points when playing, when he is not around, their lost is just 50 points.
(3) The order from increasing to the least is player A, B, D, C, E, G, F.</span>
Answer: 35
Explanation:
P(Tail) = 1/2
P(Tail) for 70 times = 1/2 x 70 = 35
Answer: 40
Step-by-step explanation:
Answer:
- 3 (die)
- 4 (slips)
- 6 (spinner)
- 5 (ace)
Step-by-step explanation:
Josie rolls a six-sided die 18 times. What is the estimated number of times she rolls a two? 3 = (1/6)(18)
Slips of paper are numbered 1 through 10. If one slip is drawn and replaced 40 times, how many times should the slip with number 10 appear? 4 = (1/10)(40)
A spinner consists of 10 equal- sized spaces: 2 red, 3 black, and 5 white. If the spinner is spun 30 times, how many times should it land on a red space? 6 = (2/10)(30)
A card is picked from a standard deck of playing cards 65 times and replaced each time. About how many times would the card drawn be an ace? 5 = (4/52)(65)
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The probability of a given event is the number of ways it can occur divided by the number of possibilities. For example, a 2 is one of 6 numbers on a die, so we expect its probability of showing up to be 1/6. The expected number of times it will show up in 18 rolls of the die is (1/6)(18) = 3.
