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Feliz [49]
4 years ago
9

Use a vertical number line to think about how to represent the situation below. Then, answer the question.

Mathematics
1 answer:
Butoxors [25]4 years ago
5 0

Answer:

-4

Step-by-step explanation:

i just did it on edge and got it right

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Help please worth 30
Rasek [7]

Answer:

A) AA postulate; 18

Step-by-step explanation:

Due to the similar triangles, we can set up the proportion and solve for x

8/(8+4) = 12/x

8/12 = 12/x

8*x = 12*12 ... cross multiply

8x = 144

x = 144/8

x = 18

7 0
3 years ago
Solve, using linear combination. <br> 5x + y = 2 <br> 4x + y = 4
Jet001 [13]
5x+y=2
4x+y=4

5x+y=2
-1( 4x+y=2)

5x+y=2
-4x-y=2

your y'all cancel out so you r left with

x=-2
then you plug the x in to one of the equations
5(-2)+y=2
-10+y=2
then add 10 to both sides
y=12

Answer: x = -2 y = 12

there's the work and all its simple you just have to figure out how to get rid of y or x ( which ever is easier) and you can figure it out after that
3 0
3 years ago
Solve the proportion and round the answer to the nearest hundredth
VashaNatasha [74]

Answer: v= 4.34

Step-by-step explanation:

5.4*4.9= 6.1v

26.46/6.1 = v

4.34= v

3 0
3 years ago
Read 2 more answers
Which of the following equations would graph a line parallel to 3Y= X +5
EastWind [94]

I don't know this one am not good a this

7 0
3 years ago
Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).
Zina [86]

we are given

\sqrt{30} *\sqrt{610}

we can radical formula

\sqrt{a} *\sqrt{b}=\sqrt{a*b}

we get

\sqrt{30} *\sqrt{610}=\sqrt{30*610}

\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}

we can  also write as

\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}

\sqrt{30} *\sqrt{610}=10\sqrt{183}............Answer


7 0
4 years ago
Read 2 more answers
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