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3 years ago

Jose earns $60 a day. After a few days. Jose has $240. How many days has Jose worked?

2 answers:

7 0

We can write this equation as 60d=b where the d represents the days he works. If he works 1 day we replace the d with a 1 and multiply 60 by 1. B would represent the balance he has after working d days. If we know he ha 240$ we can write the equation as
60d=240
We need to solve for d the number of days he worked and to do this we need to get d by itself
Divide 60 by both sides because in doing so, we will remove the 60 from d to get d alone
60d/60=240
***D=4***
Jose has worked 4 days

Phoenix [80]3 years ago

3 0

Answer:

He has worked 4 days.

Step-by-step explanation:

240 divided by 60 is 4.

If this helped I would appreciate it if you marked me brainliest. Thank you and have a nice day!

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Sphinxa [80]

Answer:

1961

Step-by-step explanation:

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ss7ja [257]

The answer to the question is B

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3 years ago

Read 2 more answers

How do i write an exponential equation with a vertical asymptote other that y=0

antiseptic1488 [7]

Lets say we have
P(x)/q(x)

vertical assymtotes are in the form x=something, not y=0
y=0 are horizontal assemtotes

so verticall assymtotes
reduce the fraction
set the denomenator equal to zero
those values that make the deomenator zero are the vertical assymtotes

the horizontal assymtote
when the degree of P(x)<q(x), then HA=0

when the degree of P(x)=q(x), then divide the leading coefient of P(x) by the leading coeficnet of q(x)
example, f(x)=(2x^2-3x+3)/(9x^2-93x+993), then HA is 2/9

ok so for vertical assymtote example
f(x)=x/(x^2+5x+6)
the VA's are at x=-3 and x=-2

horizontal assymtote
make degree same
f(x)=(3x^2-4)/(8x^2+9x),
the HA is 3/8
hope I helped, read the whole thing then ask eusiton

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4 years ago

Let R = [ 0 , 1 ] × [ 0 , 1 ] R=[0,1]×[0,1]. Find the volume of the region above R R and below the plane which passes through th

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$\langle1,0,8\rangle-\langle0,0,1\rangle=\langle1,0,7\rangle$

$\langle0,1,9\rangle-\langle0,0,1\rangle=\langle0,1,8\rangle$

Then the cross product of these two results is normal to the plane:

$\langle1,0,7\rangle\times\langle0,1,8\rangle=\langle-7,-8,1\rangle$

Let $(x,y,z)$ be a point on the plane. Then the vector connecting $(x,y,z)$ to a known point on the plane, say (0, 0, 1), is orthogonal to the normal vector above, so that

$\langle-7,-8,1\rangle\cdot(\langle x,y,z\rangle-\langle0,0,1\rangle)=0$

which reduces to the equation of the plane,

$-7x-8y+z-1=0\implies z=7x+8y+1$

Let $z=f(x,y)$ . Then the volume of the region above $R$ and below the plane is

$\displaystyle\int_0^1\int_0^1(7x+8y+1)\,\mathrm dx\,\mathrm dy=\boxed{\frac{17}2}$

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Verizon [17]

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