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LUCKY_DIMON [66]
3 years ago
6

Lexington Company engaged in the following transactions during Year 1, its first year in operation: (Assume all transactions are

cash transactions.) Acquired $3,300 cash from issuing common stock. Borrowed $2,350 from a bank. Earned $3,250 of revenues. Incurred $2,430 in expenses. Paid dividends of $430. Lexington Company engaged in the following transactions during Year 2: (Assume all transactions are cash transactions.) Acquired an additional $650 cash from the issue of common stock. Repaid $1,405 of its debt to the bank. Earned revenues, $4,650. Incurred expenses of $2,810. Paid dividends of $820. What was the net cash flow from financing activities reported on Lexington's statement of cash flows for Year 2
Business
1 answer:
ella [17]3 years ago
3 0

Answer:

($1,575)

Explanation:

The computation of net cash flow from financing activities is shown below:-

Lexington Company

Net cash flow from financing activities

Particulars                                                   Amount

Cash received from common stock           $650

Less:Cash paid for repayment of loan        ($1,405)

Less: Cash paid for dividend                       ($820)

Net cashflow from financing activities     ($1,575)

So, to reach the net cashflow from financing activities we simply added the cash received from common stock and deduct the cash paid for repayment of loan and cash paid for dividend.

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Which one of the following is a primary market transaction? Group of answer choices Sale of currently outstanding stock by a dea
trapecia [35]

Answer:

sale of a new share of stock to an individual investor

Explanation:

Securities are created in the primary market. With an IPO which stands for initial public offering, new stocks are sold to the public by companies on a first time basis.

The sale of a new share of stock in the question is an example of a primary market transaction.

6 0
4 years ago
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Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

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GalinKa [24]
The answer is true, hope that helps!!
6 0
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An employer can refuse to hire you if you refuse a drug screening test or background check.
Kruka [31]
Yes. this statement is true.
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Mumz [18]

Answer:

$4,850

Explanation:

The computation is shown below:

Total cost when the production is 13,000 units

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Direct labor $14,690

Variable overhead $16,380

Total $41,900

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In the case when the order is accepted So the net income would increased by

= $41,900 - $37,050

= $4,850

7 0
3 years ago
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