A=(pi)d
158.368=3.14d
d=50.436
r=25.218
The theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
According to the given question.
A card is drawn from a shuffled standard deck.
Since, the total number of cards in a shuffled standard deck = 52
And, the total number of aces in a shuffled standard deck = 4
As, we know that "the theoretical probability of an event is the number of desired outcomes divided by all possible outcomes".
Therefore, the theoretical probabability of drawing an ace from a shuffled deck of playing cards
= 4/52
= 1/13
Hence, the theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
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B^5 when you’re dividing exponents, just subtract!
9514 1404 393
Answer:
AE = 3
Step-by-step explanation:
First of all, we need to find corresponding sides that are defined in both figures. The table below shows the given values.
From the table, we can write the proportion ...
EA/RS = BC/TU . . . corresponding sides are proportional
EA/6 = 4/8 . . . . . . . substitute given lengths
EA = 6(4/8) = 3
The length of AE is 3 units.
Pemdas you multiply first meaning you multiply 4 and 4 getting 16 then adding 34 which is the answer to the problem
