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fomenos
3 years ago
11

A game room has a floor that is 400 feet by 90 feet. A scale drawing of the floor on grid paper uses a scale of 1 unit:5 feet. W

hat are the dimensions of the scale drawing? Enter your answer as length by width.
Mathematics
1 answer:
Allisa [31]3 years ago
4 0
First 1/5 is equivalent to 20% so to get 20% of both of them multiply by .2. so 400×.2=80 and 90×.2=18
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Find the average of$ 1148.37,$1760.44,$1143.57,and 1336.17 then round to the nearest cent
schepotkina [342]
If you total them it equals $5388.55. and then divide by 4 and the average is 1347.1375 and the you round to nearest cent. $1347.14
3 0
3 years ago
Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o
NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so \pi = 0.8.

(a) What is the probability she gets an A?

There are four problems, so n = 4

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find P(X \geq 3)

P(X \geq 3) = P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096

P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096

P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so n = 3

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find P(X \geq 2)

P(X \geq 3) = P(X = 2) + P(X = 3)

P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384

P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512

P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0
3 years ago
Select all the equations where m = 4 is a solution.
Aneli [31]
The answers are A,B, and E. Hope this helps. :)
4 0
3 years ago
The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 fe
bezimeni [28]
Assign the following variables for the origina3l rectangle:
let w = width let w + 8 = length and the area would be w(w + 8) = w² + 8w

No for the second rectangle:
let (w + 4) = width and (w + 8 - 5) or (w + 3) = length
Area = length x width or (w + 4)(w + 3) = w² + 3w + 4w + 12 using the foil method to multiply to binomials. Simplified Area = w² + 7w + 12

Now our problem says that the two area will be equal to each other, which sets up the following equation:

w² + 8w = w² + 7w + 12 subtract w² from both sides
8w = 7w + 12 subtract 7w from both sides
w = 12 this is the width of our original rectangle
recall w + 8 = length, so length of the original rectangle would be 20
7 0
3 years ago
For each of the following binomial random variables, specify n and p. (a) A fair die is rolled 50 times. X = number of times a 5
Keith_Richards [23]

Answer:

a) n = 50, p = \frac{1}{6}

b) n = 16, p = \frac{1}{100}

c) n = 26, p = 0.25, \mu = 6.5

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

(a) A fair die is rolled 50 times. X = number of times a 5 is rolled

The die is rolled 50 times, so n = 50.

Each roll can have 6 outcomes. So the probability that 5 is rolled is p = \frac{1}{6}

(b) A company puts a game card in each box of cereal and 1/100 of them are winners. You buy sixteen boxes of cereal, and X = number of times you win.

You buy 16 boxes of cereal, so n = 16.

1 of 100 are winners. So p = \frac{1}{100}.

(c) Jack likes to play computer solitaire and wins about 25% of the time. X = number of games he wins out of his next 26 games.

He plays 26 games, so n = 26.

He wins 25% of the time, so p = 0.25

We have that \mu = np. So \mu = 26*0.25 = 6.5

6 0
3 years ago
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