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tamaranim1 [39]
3 years ago
8

Find the critical value.

Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

The degrees of freedom are given by df = n-1 = 28

And since we are conducting a right tailed test we need to find in the right tail of the t distribution with 28 degrees of freedom a value who accumulates \alpha=0.005 and we got:

t_{cric}= 2.763

Step-by-step explanation:

For this case we are assuming a right tailed test for a parameter, let's say \mu

The system of hypothesis for this case are:

Null hypothesis: \mu \leq \mu_o

Alternative hypothesis: \mu > \mu_o

Where \mu_o is the value to check

The degrees of freedom are given by df = n-1 = 28

And since we are conducting a right tailed test we need to find in the right tail of the t distribution with 28 degrees of freedom a value who accumulates \alpha=0.005 and we got:

t_{cric}= 2.763

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Answer:

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Step-by-step explanation:

-4x + 6(6 - 2x) = -7x - 36

-4x + 36 - 12x = -7x - 36

-16x + 36 = -7x - 36

<u>       +36           +36</u>

-16x + 72 = -7x

<u>+16x           +16x</u>

72 = 9x

divide by 9

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The smallest square number which can be divisible by 11 and 5​
Elena L [17]

Answer:

3025

Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

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therefore the number is 55x, where x is a positive integer.

it is a said that the number is a perfect square

therefore the square root of 55x must be an integer.

\sqrt{55x}  =  \sqrt{5 \times 11 \times x}

the smallest value of x to make 55x a perfect square is....

x = 11 \times 5 = 55

Therefore the number is.... .

55x = 55(55) = 3025

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